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Wittaler [7]
3 years ago
10

Solve for x 1/3(3x + 9) =60​

Mathematics
2 answers:
juin [17]3 years ago
4 0

Congrats on your first question!

Answer: x=57

///////////////////////////////////////////////////////////////////////////////////////////////////////

1/3(3x+9)=60

x+3=60

x=57

pishuonlain [190]3 years ago
4 0

[ Answer ]

\boxed{X \ = \ 57}

[ Explanation ]

\frac{1}{3}(3x + 9) = 60

Multiply Both Sides By 3:

3 · \frac{1}{3}(3x + 9) = 60 · 3

Simplify:

3x + 9 = 180

Subtract 9 From Both Sides:

3x + 9 - 9 = 180 - 9

Simplify:

3x = 171

Divide Both Sides by 3:

\frac{3x}{3} \ = \ \frac{171}{3}

Simplify:

X = 57

\boxed{[ \ Eclipsed \ ]}

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Answer:

answer is 11 12

Step-by-step explanation:

4 0
3 years ago
A store sells 4 cans of beans for $9. What is the price of 7 cans of beans?
nirvana33 [79]
So for 4 cans of beans for $9, each can would be $2.25 so then we multiply that by 7 so it would be $15.75 for 7 cans of beans
5 0
3 years ago
Read 2 more answers
Unit 3, Lesson 7
aksik [14]

Answer:

Find the complete table in attached file.

Step-by-step explanation:

Find the Incomplete table in attached file

Given:

A car travels 55 miles per hour for 2 hours.

So the speed of the car 55 miles per hour is constant for 2 hours.

Using speed  formula.

Speed=\frac{distance}{time}

Second row.

From the second row of the table time = \frac{1}{2}=0.5\ sec and speed is constant speed = 55\ mi/hr, so we need to find only distance.

Speed=\frac{distance}{time}

55=\frac{distance}{0.5}

distance = 55\times 0.5

distance = 27.5\ mi

Third row.

From the third row of the table time =1\frac{1}{2}=\frac{3}{2} = 1.5\ sec and speed is constant speed = 55\ mi/hr, so we need to find only distance.

Speed=\frac{distance}{time}

55=\frac{distance}{1.5}

distance = 55\times 1.5

distance = 82.5\ mi

Fourth row.

From the fourth row of the table distance =110\ miles and speed is constant speed = 55\ mi/hr, so we need to find time.

Speed=\frac{distance}{time}

time=\frac{distance}{speed}

time=\frac{110}{55}

time = 2\ sec

Therefore we complete the table from the above calculation.

8 0
3 years ago
The first term of a geometric series is -3, the common ratio is 6, and the sum of the series is -4,665. Using a table of values,
tamaranim1 [39]

Answer:

Option A. 5

Step-by-step explanation:

From the question given above, the following data were obtained:

First term (a) = –3

Common ratio (r) = 6

Sum of series (Sₙ) = –4665

Number of term (n) =?

The number of terms in the series can be obtained as follow:

Sₙ = a[rⁿ – 1] / r – 1

–4665 = –3[6ⁿ – 1] / 6 – 1

–4665 = –3[6ⁿ – 1] / 5

Cross multiply

–4665 × 5 = –3[6ⁿ – 1]

–23325 = –3[6ⁿ – 1]

Divide both side by –3

–23325 / –3 = 6ⁿ – 1

7775 = 6ⁿ – 1

Collect like terms

7775 + 1 = 6ⁿ

7776 = 6ⁿ

Express 7776 in index form with 6 as the base

6⁵ = 6ⁿ

n = 5

Thus, the number of terms in the geometric series is 5.

8 0
3 years ago
A motel rents double rooms at $34 per day and single rooms at $27 per day. If 26 rooms were rented one day for a total of $807,
torisob [31]

Let, number of double rooms and single rooms are d and s.

d + s = 26     ....1 )

Hotel rents double rooms at $34 per day and single rooms at $27 per day.

34d + 27s = 807   ....2)

Solving equation 1 and 2, we get :

34( 26 - s ) + 27s = 807

884 - 34s + 27s = 807

7s = 77

s = 11

And d = 26 - 11 = 15

Therefore, number of double rooms and single rooms are 15 and 11.

Hence, this is the required solution.

4 0
3 years ago
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