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Ilya [14]
3 years ago
11

What two numbers have a product of -25 and a sum of 24?​

Mathematics
1 answer:
NemiM [27]3 years ago
7 0
-1 and 25

have a good day!
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3³y³ I'm pretty sure.

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Simplify the following expression:<br> -8 (5b + 2) -7 ( b-5)
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A billboard designer has decided that a sign should have 3 ft margins at the top and bottom and 5 ft margins on the left and rig
elixir [45]

Answer:

The width of billboard is "[x]" and the height of billboard is "[y"]. If total area of billboard is 9000 ft^2 then 9000=xy

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& y=\frac{9000}{x} \\  & A=(x-10)(y-6) \\  & A=xy-6x-10y+60 \\  & A=x\left( \frac{9000}{x} \right)-6x-10\left( \frac{9000}{x} \right)+60 \\  & A=9060-6x-\frac{9000}{x} \\

On taking the first order derivative of A

\[A'=-6+\left( \frac{90000}{{{x}^{2}}} \right)\]

& \left( \frac{90000}{{{x}^{2}}} \right)-6=0 \\          & 6{{x}^{2}}=90000 \\          & x=\sqrt{15000} \\          & y=\frac{9000}{x}=\frac{90000}{\sqrt{15000}}=10\sqrt{150} \\

• Hence \[x=10\sqrt{150}\] and \[y=\frac{900}{\sqrt{150}}\]

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The maximum afternoon temperature in Granderson is modeled by t=60-30 cos (x<img src="https://tex.z-dn.net/?f=%20%5Cpi%20" id="T
kicyunya [14]
The equation is t=60-30 cos (x \frac{\pi}{6})

the -30 expression, is subtracting, if negative, from the 60
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and then the 30 expression will ADD to the 60 amount
so the temperature "t" is highest, when the 30 expression, is
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when does that happen, when cosine is negative and at its highest,
well, cosine range is -1\le cos(\theta ) \le 1
so the lowest value cosine can provide is -1, when is cosine -1?
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so...  let's find a value that makes that expression to cos(\pi)

\bf t=60-30 cos (x \frac{\pi}{6}) \qquad x=6&#10;\\\\&#10;thus&#10;\\\\&#10;t=60-30 cos (6 \frac{\pi}{6})\implies t=60-30 cos (\pi )&#10;\\\\&#10;t=60-30[-1]\implies t=60+30\implies t=90

----------------------------------------------------------------------------------------
so...for August, that'll mean


\bf t=60-30 cos (x \frac{\pi}{6}) \qquad x=7&#10;\\\\&#10;t=60-30 cos (\frac{7\pi}{6})\implies t=60-30\left( -\cfrac{\sqrt{3}}{2} \right)&#10;\\\\&#10;t=60+(15\cdot \sqrt{3})\implies t\approx85.98^o


4 0
3 years ago
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