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3 years ago

15

John gave Peter 2/5 of his CDs

1 answer:

Zigmanuir [339]3 years ago

7 0

Answer:

1/5 Maybe?, im not entirely sure sorry ._.'

Step-by-step explanation:

2/5

1/5

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How to differentiate y=x^n using the first principle. In this question, I cannot use the rule of differentiation. I have to do t

Zarrin [17]

By first principles, the derivative is

$\displaystyle\lim_{h\to0}\frac{(x+h)^n-x^n}h$

Use the binomial theorem to expand the numerator:

$(x+h)^n=\displaystyle\sum_{i=0}^n\binom nix^{n-i}h^i=\binom n0x^n+\binom n1x^{n-1}h+\cdots+\binom nnh^n$

$(x+h)^n=x^n+nx^{n-1}h+\dfrac{n(n-1)}2x^{n-2}h^2+\cdots+nxh^{n-1}+h^n$

where

$\dbinom nk=\dfrac{n!}{k!(n-k)!}$

The first term is eliminated, and the limit is

$\displaystyle\lim_{h\to0}\frac{nx^{n-1}h+\dfrac{n(n-1)}2x^{n-2}h^2+\cdots+nxh^{n-1}+h^n}h$

A power of $h$ in every term of the numerator cancels with $h$ in the denominator:

$\displaystyle\lim_{h\to0}\left(nx^{n-1}+\dfrac{n(n-1)}2x^{n-2}h+\cdots+nxh^{n-2}+h^{n-1}\right)$

Finally, each term containing $h$ approaches 0 as $h\to0$ , and the derivative is

$y=x^n\implies y'=nx^{n-1}$

4 0

3 years ago

Help Q-Q 7/10c =4 1/5

shepuryov [24]

$\huge\mathfrak\green{answer}$

$= q - \frac{q7}{10} c = \frac{41}{5}$

$\red{multiply}$

$= q - \frac{cq7}{10} = \frac{41}{5}$

$\red{subtract \: q \: from \: both \: sides}$

$= q - \frac{cq7}{10} - q = \frac{41}{5} - q$

$\red{now \: simplify}$

$= - \frac{cq7}{10} = \frac{41}{5} - q$

$\red{multiply \: 10 \: both \: sides}$

$= 10( - \frac{cq7}{10} ) = 10. \frac{41}{5} - 10q$

$\red{simplify}$

$= - cq7 = 82 - 10q$

$\red{now \: divide}$

$= \frac{ - cq7}{ - q7} - \frac{82}{ - q7} - \frac{10q}{ - q7}$

$\red{simplify}$

$= c = - \frac{82 - 10q}{q7} (q≠0)$

Brainliest? :) (I'd really appreciate if you mark me as brainliest)

$\huge\mathfrak\green{thank \: you}$

5 0

3 years ago

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Help please! Identify an equation in point slope form for the line perpendicular to Y =-4x + 8 that passes through (-2, 7)

777dan777 [17]

Answer:

D. $y-7=\frac{1}{4}(x+2)$

Step-by-step explanation:

The point-slope form of a line is given by:

$y-y_1=m(x-x_1)$

The line given to us has equation; $y=-4x+8$ .

The slope of this line is -4. The of the line perpendicular to this line is the negative reciprocal of the slope of the given line.

Our slope of interest is therefore; $m=\frac{1}{4}$

Since the point goes through (-2,7), we have $x_1=-2,y_1=7$ .

We plug in the slope and the point into the point-slope formula to obain;

$y-7=\frac{1}{4}(x--2)$

The required equation is:

$y-7=\frac{1}{4}(x+2)$

3 0

3 years ago

How to solve the following equation:

boyakko [2]

43454223456653466777

3 0

3 years ago

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Find the inverse of the function g(x)=(x-4)^2+11

dusya [7]

Answer:

y= $\sqrt{x-11} - 4$

Step-by-step explanation:

switch the x and y and solve for y.

4 0

3 years ago