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3 years ago

Conver the equation y=2 to polar form. Then solve the resulting equation for r. Thanks :)

Mathematics

1 answer:

maksim [4K]3 years ago

8 0

This is something to memorize

y = r*sin(theta)

so if y = 2, then

2 = r*sin(theta)

Divide both sides by sin(theta) to get

r = 2/sin(theta)
r = 2csc(theta)

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Motorola used the normal distribution to determine the probability of defects and the number

vovangra [49]

Answer:

a.P<x<9.85 orx>10.15)=0.3174, Total defects=317.4

b.p=0.0026,total defects=2.6

c.Less of the items produced will be classified as defects.

Step-by-step explanation:

a.The standard score,z, is esentially x reduced by process mean then divided my process standard deviation.

$\mu=10,\sigma=0.15\\Therefore:-\\z=\frac{x-\mu}{\sigma}=\frac{9.85-10}{0.15}\approx-1.0\\z=\frac{x-\mu}{\sigma}=\frac{10.15-10}{0.15}\approx+1.0\\P(x10.15)=P(Z+1.0)\\=2P(Z$

Total defects=Production*Probability

=0.3174*1000

$=317.4$

b. $\mu=10,\sigma=0.05$

therefore:-

$z=\frac{x-\mu}{\sigma}=\frac{9.85-10}{0.05}\approx-3.0\\z=\frac{x-\mu}{\sigma}=\frac{10.15-10}{0.05}\approx+3.0\\\\=P(x10.15)=P(Z+3.0)\\=2P(Z$

Defects=Probability*Production

=0.0026*1000

=2.6

c.Reducing process variation results in a significant reduction in the number of unit defects.

3 0

3 years ago

Please help me with this! if you do you will get brainliest

VLD [36.1K]

Answer:

not -7 just 7

Step-by-step explanation:

3 0

3 years ago

What do we call financial assistance for a student who meets academic, athletic, or talent requirements to help pay for college

sladkih [1.3K]

This is a scholarship.

Student loans must be repaid; grants are given usually without those types of restrictions; and student work involves a student having an on-campus job.

8 0

3 years ago

Solve for x <br> 8x+1>−31

slavikrds [6]

$8x + 1 > - 31 \\ 8x > - 1 - 31 \\ 8x > - 32 \\ x > \frac{ - 32}{8} \\ x > - 4$

3 0

3 years ago

Donatello Co. has identified an activity cost pool to which it has allocated estimated overhead of $9,600,000. It has determined

ahrayia [7]

Answer:

option (a) Widgets $2,400,000, Gadgets $1,800,000, Targets $5,400,000

Step-by-step explanation:

Data provided in the question:

Allocated estimated overhead = $9,600,000

Expected use of cost drivers for the activity = 800,000 inspections.

Inspections required by Widgets = 200,000

Inspections required by Gadgets = 150,000

Inspections required by Targets = 450,000

Therefore,

Total overhead per activity = $\frac{\textup{estimated overhead}}{\textup{Total activity}}$

= $\frac{\textup{9,600,000}}{\textup{800,000 }}$

= $12 per activity

Thus,

Overhead allocated to Widgets = 200,000 × 12 = $2,400,000

Overhead allocated to Gadgets = 150,000 × 12 = $1,800,000

Overhead allocated to Target = 450,000 × 12 = $5,400,000

Hence, The correct answer is option (a)

8 0

3 years ago