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Alja [10]
3 years ago
6

Once upon a time I weighed 120 pounds. Now I weigh 225 pounds. What is the percent change?

Mathematics
2 answers:
amm18123 years ago
7 0

Answer:

The percent change is 87.5%. (You're one chonky boi lol)

Step-by-step explanation:

To find the percent change, calculate the difference between the new weight and the old weight and divide that value by the old weight and multiply by 100% to find the percent change. In this case, the equation would be \frac{225-120}{120} * 100% = \frac{105}{120} * 100% = 0.875 * 100% = 87.5%, so the correct answer is a percent change of 87.5%.

sveticcg [70]3 years ago
7 0

Answer:

53\frac{1}{3} %

Step-by-step explanation:

\frac{120}{225} =\frac{y}{100}

225 × y = 120 × 100

225y = 12000

225y ÷ 225 = 12000 ÷ 225

y=53\frac{1}{3}

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F(v)=6+v^2 how do I solve
Nostrana [21]

Step-by-step explanation:

Well, this is a function. In order to solve this, you need a v value. Once you get a v value, you can plug into into 6+v^2 and wala- you get your answer.

Example, lets say

v is 3

then

F(3) = 6 + 3^2

f(3) = 6 + 9

f(3) =15

Hope this helped

6 0
3 years ago
At the end of the school year a school system has a table with the total absences and tardies in its 10 schools what is the best
enot [183]

Answer:

A

Step-by-step explanation:

3 0
3 years ago
I need to show work and Idk how for 2 or 3. The -5,-2 and 8,3 is the answers just need work shown thanks
prisoha [69]
#2
2x - 4y = -2
2x + 3y = -16
------------------subtract
-7y = 14
y = 14/-7
y = -2

2x - 4y = -2
2x - 4(-2) = -2
2x + 8 = -2
2x = -2 -8
2x = -10
x = -10/2
x = -5
answer x = -2 and y = -5

check:

2(-5)- 4(-2) = -2
-10 +8 = -2
-2 = -2.....true

2x + 3y = -16
2(-5)+3(-2) = -16
-10 + (-6) = -16
-16 = -16...true


3 0
3 years ago
Write an expression for 213 increased by d.
Tcecarenko [31]

Write an expression for 213 increased by d: 213+d=x

6 0
3 years ago
Suppose F⃗ (x,y)=⟨ex,ey⟩F→(x,y)=⟨ex,ey⟩ and CC is the portion of the ellipse centered at the origin from the point (0,1)(0,1) to
Rudik [331]

Probably the intended ellipse is the one with equation

\dfrac{x^2}{49}+y^2=1

We can parameterize C as a piece of this curve by

\vec r(t)=\langle7\sin t,\cos t\rangle

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\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\int_0^{\pi/2}\langle e^{7\sin t},e^{\cos t}\rangle\cdot\langle7\cos t,-\sin t\rangle\,\mathrm dt

etc

7 0
3 years ago
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