How many elements must a set have if the number of proper subsets of the set is one half of the total number of subsets of the
1 answer:
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9514 1404 393
Answer:
7 7/8
Step-by-step explanation:
There are several ways to get there.
2.25×3.5 = 7.875 = 7 7/8
(2 1/4)(3 1/2) = (9/4)(7/2) = 63/8 = 7 7/8
(2 1/4)(3.5) = 2(3.5) +(1/4)(3.5) = 7 + (2·3.5)/(2·4) = 7 +7/8 = 7 7/8
A typical graphing calculator will let you enter this problem directly, giving you a result either as a decimal, improper fraction, or a mixed number.
