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mestny [16]
3 years ago
15

How many numbers between 111 and 100100100 (inclusive) are divisible by 444 or 999?

Mathematics
1 answer:
FrozenT [24]3 years ago
6 0

Answer:

100100100/999=100,200

100100100=225,450

325,650 would be your answer

Step-by-step explanation:

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Plz help with these first one gets brainliest
vlabodo [156]

Answer:

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Step-by-step explanation:

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(1 point) Consider the function f(x)=2x3−9x2−60x+1 on the interval [−4,9]. Find the average or mean slope of the function on thi
OlgaM077 [116]

Answer: c = 4.97 and c = -1.97

Step-by-step explanation: <u>Mean Value Theorem</u> states if a function f(x) is continuous on interval [a,b] and differentiable on (a,b), there is at least one value c in the interval (a<c<b) such that:

f'(c) = \frac{f(b)-f(a)}{b-a}

So, for the function f(x) = 2x^{3}-9x^{2}-60x+1 on interval [-4,9]

f'(x) = 6x^{2}-18x-60

f(-4) = 2.(-4)^{3}-9.(-4)^{2}-60.(-4)+1

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Calculating average:

6c^{2}-18c-60 = \frac{100-113}{9-(-4)}

6c^{2}-18c-60 = -1

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Resolving through Bhaskara:

c = \frac{18+\sqrt{1740} }{12}

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c = \frac{18-41.71 }{12} = -1.97

<u>Both values of c exist inside the interval [-4,9], so both values are mean slope: c = 4.97 and c = -1.97</u>

7 0
4 years ago
How to solve this Algebra question?
PIT_PIT [208]
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artcher [175]

Answer:

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Answer:

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