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pentagon [3]
3 years ago
12

Which eukaryotic kingdom includes members that are the result of endosymbioses that included an ancient aerobic bacterium and an

ancient cyanobacterium?
Biology
1 answer:
ElenaW [278]3 years ago
5 0
The answer to this question is : <span>Plantae</span>
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A scientist used a radioactive isotope of nitrogen to label the nitrogenous bases of the DNA in bacterial cells. The labeled cel
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Answer:

<h2>D.  Radioactive nitrogen in the DNA of the bacterial cells is present in one strand of the DNA of all of the cells.</h2>

Explanation:

As given here,

The nitrogenous base of DNA is radio active labeled, and is grown in normal unlabeled medium.

As we know that DNA replication occurs in semi-conservative way, so after one round of replication, one parental strand would be radio active and other newly synthesized strand would be unlabeled.

So here, after one round of replication, one strand of all the newly synthesized DNA would be radio active and other strand would be normal.

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What kind of mixture can paint be classified as
Travka [436]

Answer:

colloid

Explanation:

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The answer is electrostatic precipitator

hope this helps :)

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3 years ago
HELP NEEDED QUICK
Karolina [17]

Answer:

they are heterotrophic and can produce their own food unlike things like microbes who rely on other things to live. they are also multicellular unlike most bacteria (mushroom is an exception)

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In genetic engineering, the structures called “sticky ends” result from what process? the results of mRNA after post-transcripti
AlexFokin [52]

Answer:

Option). the uneven cutting by most restriction enzymes

Explanation:

Sticky ends can be defined as over-hanged DNA fragments of unequal length, having a terminal portion with unpaired nucleotides. These fragments are formed by a staggered cut on DNA molecules wit the help of restriction endonuclease enzymes.

These ends have complementary nucleotide bases that allow complementary base pairing between bases, and thus, known as sticky ends.  

Thus, the correct answer is 'last option.'

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