All categories

3 years ago

Need help with all questions

Mathematics

1 answer:

Vesnalui [34]3 years ago

5 0

Answer:

14, 15

Step-by-step explanation:

You might be interested in

Make a conjecture must the difference between two rational numbers be rational number? Explain

Scilla [17]

Answer:

Yes, the difference of two rational numbers is a rational number. The reason for this lies in the following facts: The product of two integers is an integer. The difference between two integers is an integer.

Step-by-step explanation:

6 0

4 years ago

A bag of dog food says that it now contains 20% more. Originally, it came with 63 ounces of dog food. How much dog food does the

Brrunno [24]

Answer:

75.6 ounces

Step-by-step explanation:

Step one.

Given data

we are told that the original quantity of food is 63 ounces

and the increase is in food is by 20%

Step two:

let us find the increase in ounces

=20/100*63

=0.2*63

=12.6 ounces

Hence the amount of food in the bag now is

=12.6+63

=75.6 ounces

5 0

3 years ago

HELLO PLEASE HELP!! HAVE A GOOD DAY/NIGHT!!

aliina [53]

So, XZ= 7x+1 and PZ= 4x-1. To figure out XP we have to subtract those two.

(7x+1)-(4x-1)

3x-2

3(8)-2

24-2

XP=22

6 0

3 years ago

Read 2 more answers

Convert the polar equation r = 2 secØ to a Cartesian equation.y = 2x = 2x^2 = 2

ss7ja [257]

Polar and cartesian equation<h2>Initial explanation</h2>

Let's analyze the relation between r and x and y:

We have that between the indicated value of r (of the polar coordinates) and x and y (of the cartesian coordinates) there is a relation because they form a triangle. If r changes, then the value of x and y will change.

<h2>STEP 1: given equation</h2>

Using the given equation

r = 2 secØ

we have that

$\begin{gathered} r=2secØ \\ \downarrow \\ \frac{r}{2}=secØ \end{gathered}$ <h2>STEP 2: secØ equation</h2>

Observing the image of the initial explanation we have a right triangle, we know that the equation of

secØ for any right triangle is given by:

$\sec Ø=\frac{\text{hypotenuse}}{\text{adjacent side}}$

In this case,

hypotenuse = r

adjacent side = x

then,

$\begin{gathered} \sec Ø=\frac{\text{hypotenuse}}{\text{adjacent side}}=\frac{r}{x} \\ \sec Ø=\frac{r}{x} \end{gathered}$ <h2>STEP 3: comparison between given equation and secØ equation</h2>

Then, we have that: