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Ksju [112]
3 years ago
14

12. Carmen multiplied a non-zero rational number by its additive inverse. Which statement about the product must be true?

Mathematics
1 answer:
nignag [31]3 years ago
6 0

Answer:

<u>Option C. The product was negative.</u>

Step-by-step explanation:

Let the non-zero rational number is = \frac{x}{y}

So, its additive inverse = -\frac{x}{y}

The result of multiplication the non-zero rational number by its additive inverse = \frac{x}{y} *-\frac{x}{y} =-\frac{x^2}{y^2}

We will check the options:

A. The product was the multiplicative inverse of the original number.

<u>Wrong </u>because the product = \frac{x}{y} *-\frac{x}{y} =-\frac{x^2}{y^2}

B. The product was the additive inverse of the original number.

<u>Wrong </u>because the product = \frac{x}{y} *-\frac{x}{y} =-\frac{x^2}{y^2}

C. The product was negative.

<u>True</u>

D. The product was positive.

<u>Wrong </u>because the product was negative.

<u>So, the answer is option C.</u>

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Now, each of the semicircles has a diameter of 58m, and we have that the area of a circle is equal to:

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The perimeter of an equilateral triangle is 3 (+ 5). The perimeter of a rectangle is 2 (2x - 3) + 2(2). If the perimeters of the
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Answer:

Vertices at (-7, 5) and (-1, 5).

Foci at (-9, 5) and (1,5).

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The standard form for the equation of a hyperbola with centre (h, k) is

(x - h²)/a² - (y - k)²/b² = 1

Your hyperbola opens left/right, because it is of the form x - y.

Comparing terms, we find that

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The coordinates of the foci are (-9, 5) and (1, 5).

The Figure below shows the graph of the hyperbola with its vertices and foci.

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