Assuming the question marks are minus signs
to find max, take derivitive and test 0's and endpoints
take derivitive
f'(x)=18x²-18x-108
it equal 0 at x=-2 and 3
if we make a sign chart to find the change of signs
the sign changes from (+) to (-) at x=-2 and from (-) to (+) at x=3
so a reletive max at x=-2 and a reletive min at x=3
test entpoints
f(-3)=83
f(-2)=134
f(3)=-241
f(4)=-190
the min is at x=3 and max is at x=-2
Answer:
D. They have the same y-intercep
Step-by-step explanation:
Before the comparison will be efficient, let's determine the equation of the two points and the x intercept .
(–2, –9) and (4, 6)
Gradient= (6--9)/(4--2)
Gradient= (6+9)/(4+2)
Gradient= 15/6
Gradient= 5/2
Choosing (–2, –9)
The equation of the line
(Y+9)= 5/2(x+2)
2(y+9)= 5(x+2)
2y +18 = 5x +10
2y =5x -8
Y= 5/2x -4
Choosing (4, 6)
The equation of line
(Y-6)= 5/2(x-4)
2(y-6) = 5(x-4)
2y -12 = 5x -20
2y = 5x-8
Y= 5/2x -4
From the above solution it's clear that the only thing the both equation have in common to the given equation is -4 which is the y intercept
1 3/9 but if reduce to lowest term than 1 1/3
Answer:
see below
Step-by-step explanation:
The slopes of parallel lines are the same. The slopes of perpendicular lines are negative reciprocals of each other, hence their product is -1.
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For the most part, the concept of adding slopes of lines does not relate to parallel or perpendicular lines in any way.
Answer:
U ={ Parallelograms}
A= { Parallelogram with four congruent sides}={ Rhombus,Square}
B ={ Parallelograms with four congruent angles} ={ Rectangle, Square}
So, AB= { Square}
So among all the parallelograms "Square" is the only parallelogram which has all congruent sides as well as all congruent angles.
