1/6th is the answer in simplest form.
Answer: Our required probability is 0.83.
Step-by-step explanation:
Since we have given that
Number of dices = 2
Number of fair dice = 1
Probability of getting a fair dice P(E₁) = 
Number of unfair dice = 1
Probability of getting a unfair dice P(E₂) = 
Probability of getting a 3 for the fair dice P(A|E₁)= 
Probability of getting a 3 for the unfair dice P(A|E₂) = 
So, we need to find the probability that the die he rolled is fair given that the outcome is 3.
So, we will use "Bayes theorem":

Hence, our required probability is 0.83.
Answer:
(-2,12)
Step-by-step explanation:
Answer:
Step-by-step explanation:
Probability of of winning next shot if he scores= 0.5
Probability of missing next shot if he misses = 1/6
a) Probability of scoring 2 shots later if he missed = (1-1/6)^2
=(5/6)^2
=25/36
b) % of successful shots= (1/2+5/6×(1/100))%
=4/3×1/100
=0.013%
Answer:
2) Yes it is
Step-by-step explanation:
One is just cutting the same peices into smaller ones. This does not change the result!