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3 years ago

12

jan work 4 hours on a job and ted worked 5 hours both were paid the same hourly rate together they earned $31.50 how much did ea

ch receive

1 answer:

TiliK225 [7]3 years ago

8 0

This could by seen as a ratio:
4:5

Add up the ratio. Then divide the money earned, by the ratio.
4 + 5 = 9
31.50 / 9 = 3.5

Then you times the individual hours by this.
4 x 3.5 = $14
5 x 3.5 = $17.5

So Jan earned $14
And Ted earned $17.50

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Brian recorded the number of commercials played during two types of television shows: an educational documentary and a primetime

Sladkaya [172]

Answer:

$m(x)_A = 5.2$ --- Mean absolute deviation of educational documentary

$m(x)_B = 4.7$ --- Mean absolute deviation of prime time drama

Step-by-step explanation:

Given

$n = 10$

See attachment for table

Required

Determine the mean absolute deviation of each

Mean absolute deviation m(x) is calculated as:

$m(x) = \frac{1}{n}\sum |x - \mu|$

For Educational Documentary

First, calculate the mean

$\mu = \frac{\sum x}{n}$

So:

$\mu_A = \frac{26 + 28 + 30 + 18+27 + 18 + 20 +31+17+17}{10}$

$\mu_A = \frac{232}{10}$

$\mu_A = 23.2$

The mean absolute deviation is then calculated as:

$m(x)_A = \frac{1}{n}\sum |x - \mu_A|$

$m(x)_A = \frac{1}{10}(|26 -23.2| +|28 -23.2| +|30 -23.2| +|18 -23.2| +|27 -23.2| +|18 -23.2| +|20 -23.2| +|31 -23.2| +|17 -23.2| +|17 -23.2|)$

$m(x)_A = \frac{1}{10}(|2.8| +|4.8| +|6.8| +|-5.2| +|3.8| +|-5.2| +|-3.2| +|7.8| +|-6.2| +|-6.2|)$

$m(x)_A = \frac{1}{10}(2.8 +4.8 +6.8 +5.2 +3.8 +5.2 +3.2 +7.8 +6.2 +6.2)$

$m(x)_A = \frac{1}{10}*52$

$m(x)_A = 5.2$

For Prime time Drama

First, calculate the mean

$\mu = \frac{\sum x}{n}$

So:

$\mu_B = \frac{39+39+35+29+40+27+41+29+32+30}{10}$

$\mu_B = \frac{341}{10}$

$\mu_B = 34.1$

The mean absolute deviation is then calculated as:

$m(x)_B = \frac{1}{n}\sum |x - \mu_B|$

$m(x)_B = \frac{1}{10}(|39-34.1|+|39-34.1|+|35-34.1|+|29-34.1|+|40-34.1|+|27-34.1|+|41-34.1|+|29-34.1|+|32-34.1|+|30-34.1|)$

$m(x)_B = \frac{1}{10}(|4.9|+|4.9|+|0.9|+|-5.1|+|5.9|+|-7.1|+|6.9|+|-5.1|+|-2.1|+|-4.1|)$

$m(x)_B = \frac{1}{10}(4.9+4.9+0.9+5.1+5.9+7.1+6.9+5.1+2.1+4.1)$

$m(x)_B = \frac{1}{10}*47$

$m(x)_B = 4.7$

6 0

3 years ago

How do i find the benchmark number between 170 and 410 using tens and hundreds

Nina [5.8K]

The answer is 290 but I solved this by mean

6 0

3 years ago

How many<br>weeks are there in 81 days

natima [27]

Answer: At least 8

Reason: A week has 7 days in it, so when you divide 81 by 7, you get 7.5, so when you round it, you get the number 8

<u><em>If you have any questions, corrections, or problems, let me know. I hope this helped</em></u>

4 0

2 years ago

A video rental store has 6,000 movies. One Friday, 3/5 of the movies were rented. How many movies were rented that Friday night?

AleksAgata [21]

6000/ 5 = 1200 x 3 =3600 movies

8 0

3 years ago

Read 2 more answers

Solve for x.<br><br> 4(x−214)=−3.7<br><br> Enter your answer as a decimal in the box.<br><br> x =

andre [41]

X = 213.075
First you have to get rid of the 4 and since it’s multiplying you to the opposite and that’s dividing.
-3.7 divided by 4 = -0.925
X - 214 = -0. 925
Then you add 214 to -0.925 and get 213.075

7 0

2 years ago