Answer:
Use 49 ounces of the 14% allow and 41 ounces of the 23% alloy.
Step-by-step explanation:
Each ounce of the 14% copper contains 0.14 ounce of pure copper.
Each ounce of the 23% copper contains 0.23 ounce of pure copper.
Each ounce of the 18.1% copper contains 0.181 ounce of pure copper.
Use x ounces of the 14% and y ounces of the 23% to make 90 ounces of 18.1% alloy.
x+y = 90
y = 90-x
0.14x + 0.23y = 0.181·90
0.14x + 0.23(90-x) = 16.29
0.14x + 20.7 - 0.23x = 16.29
-0.09x + 20.7 = 16.29
4.41 = 0.09x
x = 49
y = 90-x = 41
Use 49 ounces of the 14% allow and 41 ounces of the 23% alloy.
The straight line ON has the following equation :
(x - 18)/(x - 0) = (y - 12)/(y - 0)
Where (18,12) are coordinates of N and (0,0) are coordinates of O.
x - 18/x = y - 12/y
-18y = - 12x
y =12x/18 - - - - - (a)
The coordinates satisfy equation (a) are (7.5, 5)
Therefore D is the correct answer.
Good luck
Answer:
no
Step-by-step explanation:
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