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ahrayia [7]
3 years ago
12

Round 1289.48 to the nearest dollar please

Mathematics
2 answers:
Ilya [14]3 years ago
8 0
$1290 or you could use 1289.50
svp [43]3 years ago
5 0

Answer:

$1,289 is your answer.

Step-by-step explanation:

Since the 4 is less than 5, the 9 stays a 9.

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Consider a game in which players roll a number cube to determine the number of points earned. If a player rolls a prime number,
Aleksandr-060686 [28]

Answer:

The expected value of the points earned on a single roll in this game is \dfrac{1}{6} = 0.1667 .

Step-by-step explanation:

We are given that consider a game in which players roll a number cube to determine the number of points earned. If a player rolls a prime number, that many points will be added to the player’s total. Any other roll will be deducted from the player’s total.

Assuming that the numbered cube is a dice with numbers (1, 2, 3, 4, 5, and 6).

Here, the prime numbers are = 1, 2, 3 and 5

Numbers which are not prime = 4 and 6

This means that if the dice got the number 1, 2, 3 or 5, then that many points will be added to the player’s total and if the dice got the number 4 or 6, then that many points will get deducted from the player’s total.

Here, we have to make a probability distribution to find the expected value of the points earned on a single roll in this game.

Note that the probability of getting any of the specific number on the dice is   \dfrac{1}{6} .

      Numbers on the dice (X)                       P(X)

                      +1                                                 \frac{1}{6}

                      +2                                                \frac{1}{6}

                      +3                                                \frac{1}{6}

                      -4                                                 \frac{1}{6}

                      +5                                                \frac{1}{6}

                      -6                                                 \frac{1}{6}

Here (+) sign represent the addition in the player's total and (-) sign represents the deduction in the player's total.

Now, the expected value of X, E(X)  =  \sum X \times P(X)

   =  (+1) \times \frac{1}{6} +(+2) \times \frac{1}{6} +(+3) \times \frac{1}{6} +(-4) \times \frac{1}{6} +(+5) \times \frac{1}{6} +(-6) \times \frac{1}{6}

   =  \frac{1}{6} + \frac{2}{6} + \frac{3}{6} - \frac{4}{6} + \frac{5}{6} - \frac{6}{6}

   =  \frac{1+2+3-4+5-6}{6}

   =  \frac{11-10}{6}= \frac{1}{6}

Hence, the expected value of the points earned on a single roll in this game is  \frac{1}{6} = 0.1667 .

4 0
3 years ago
A group of biologists found a total of 15 loggerhead turtle nests along a beach during a certain season. This was 20% of the tot
Andre45 [30]
20% also equals 1/5, right?

So in order to find the total number of turtle nests, just find 5/5, or multiply 15 by 5.

15 x 5 = 75

There were 75 total nests
6 0
3 years ago
Which are ways to decompose the composite figure into simpler shapes that you have area formulas for? Check all that apply.
Oksanka [162]

Answer:

1st  and second, unless you have already learned area of trapezoids. If you have, add third

Step-by-step explanation:

4 0
3 years ago
Need help on 2, b, c, and 3 please.
Svetlanka [38]
A/Wall if you have 20 and 30 that box is missing # so you will need to times and you will get something like this 20×30=60 and that's the missing #

B/Its going to be about 768 so you need to times and if you don't get 768


4 0
3 years ago
The relation ((6, 8), (7, 10), (7, 12), (8, 16),
Brilliant_brown [7]

Answer:

x = 7 is repeated twice.

Hence, there is NO MORE unique input. We can not have repeated inputs.

Thus, the relation is NOT a function.

Step-by-step explanation:

Given the relation

  • {(6, 8), (7, 10), (7, 12), (8, 16), (10, 16)}

We know that a relation is a function that has only one output for any unique input.

As the inputs or x-values of the relations are:

at x = 6, y = 8

at x = 7, y = 10

at x = 7, y = 12

at x = 8, y = 16

at x = 10, y = 16

If we closely observe, we can check that there is a repetition of x values.

i.e. x = 7 is repeated twice.

Hence, there is NO MORE unique input. We can not have repeated inputs.

Thus, the relation is NOT a function.

8 0
3 years ago
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