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Mkey [24]
3 years ago
15

. Mrs. Khan makes cookies for the school bake sale. She uses the equation c = 0.75x to determine the cost, c, for x cookies. Whi

ch best represents the constant rate at which cookies are sold at the bake sale?
A. 75 cookies per dollar
B. (0,0), (3, 2.25), (6, 4.25), (8,6.5)
c. 3/4 cookie per dollar
D. (0,0), (2, 1.5) (5, 3.75), (7,5.25) ​
Mathematics
1 answer:
IRINA_888 [86]3 years ago
3 0

Answer:

The answer is D.

Step-by-step explanation:

You might be interested in
What is the value of X<br> 8+4x+2+56-42x
Stels [109]

Answer:

i cannot answer the value of X unless there is an equal sign but the equation simplified is 66-38x

Step-by-step explanation:

3 0
3 years ago
Um homem está localizado a 300 m de uma estrada linear (reta). Nessa estrada está localizada a sua esposa a 500 m do homem. Ambo
lukranit [14]

Answer:

The distance of the restaurant from the man and woman = 312.5 m

Option C is correct.

A distância do restaurante do homem e da mulher = 312,5 m

A opção C está correta.

Step-by-step explanation:

English Translation

A man is located 300 m from a linear (straight) road. On that road his wife is located 500 m from the man. Both walk towards a restaurant that is on the road and is the same distance from the two. What is this distance in meters?

A) 400m

B) 300m

C) 312.5m

D) 325m

E) 87.5m

Solution

A diagram showing the scenario described, is presented the attached image.

From the attached image, x is the distance of the restaurant from both the man and the woman. So, there are two right angled triangles,

- The bigger one with hypotenuse 500 m and other side 300 m, the third side is calculated as

(Third side)² = 500² - 300² = 160000

Third side = 400 m

- The smaller right angled triangle, with hypotenuse x m and other sides 300 m & (400 - x) m

(400 - x)² + 300² = x²

160000 - 800x - x² + 90000 = x²

800x = 160000 + 90000 = 250000

x = (250000/800) = 312.5 m

Hence, the distance of the restaurant from the man and woman = 312.5 m

In Portugese/Em português

Um diagrama mostrando o cenário descrito é apresentado na imagem em anexo.

Na imagem em anexo, x é a distância do restaurante do homem e da mulher. Então, existem dois triângulos retângulos,

- Quanto maior com hipotenusa 500 me outro lado 300 m, o terceiro lado é calculado como

(Terceiro lado) ² = 500² - 300² = 160000

Terceiro lado = 400 m

- O triângulo angular direito menor, com hipotenusa x me outros lados 300 m & (400 - x) m

(400 - x)² + 300² = x²

160000 - 800x - x² + 90000 = x²

800x = 160000 + 90000 = 250000

x = (250000/800) = 312.5 m

Portanto, a distância do restaurante do homem e da mulher = 312,5 m

Hope this Helps!!!

Espero que isto ajude!!!

4 0
3 years ago
How to find the lateral area and surface area of prism
Alona [7]
U find the surface of the area
6 0
3 years ago
A student at a four-year college claims that mean enrollment at four-year colleges is higher than at two-year colleges in the Un
WINSTONCH [101]

Answer:

Part 1: The statistic

t=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}} (1)  

And the degrees of freedom are given by df=n_1 +n_2 -2=35+35-2=68  

Replacing we got

t=\frac{(5135-4436)-0}{\sqrt{\frac{783^2}{35}+\frac{553^2}{35}}}}=4.31  

Part 2: P value  

Since is a right tailed test the p value would be:  

p_v =P(t_{68}>4.31)=0.000022 \approx 0.00002  

Comparing the p value we see that is lower compared to the significance level of 0.01 so then we can reject the null hypothesis and we can conclude that the mean for the four year college is significantly higher than the mean for the two year college and then the claim makes sense

Step-by-step explanation:

Data given

\bar X_{1}=5135 represent the mean for four year college

\bar X_{2}=4436 represent the mean for two year college

s_{1}=783 represent the sample standard deviation for four year college

s_{2}=553 represent the sample standard deviation two year college

n_{1}=35 sample size for the group four year college

n_{2}=35 sample size for the group two year college

\alpha=0.01 Significance level provided

t would represent the statistic (variable of interest)  

System of hypothesis

We need to conduct a hypothesis in order to check if the mean enrollment at four-year colleges is higher than at two-year colleges in the United States , the system of hypothesis would be:  

Null hypothesis:\mu_{1}-\mu_{2}\leq 0  

Alternative hypothesis:\mu_{1} - \mu_{2}> 0  

We can assume that the normal distribution is assumed since we have a large sample size for each case n>30. So then the sample mean can be assumed as normally distributed.

Part 1: The statistic

t=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}} (1)  

And the degrees of freedom are given by df=n_1 +n_2 -2=35+35-2=68  

Replacing we got

t=\frac{(5135-4436)-0}{\sqrt{\frac{783^2}{35}+\frac{553^2}{35}}}}=4.31  

Part 2: P value  

Since is a right tailed test the p value would be:  

p_v =P(t_{68}>4.31)=0.000022  

Comparing the p value we see that is lower compared to the significance level of 0.01 so then we can reject the null hypothesis and we can conclude that the mean for the four year college is significantly higher than the mean for the two year college and then the claim makes sense

6 0
3 years ago
Find all of the x-intercepts of the polynomial function <br>p(x) = 3x^3-23x^2+33x–5​
kari74 [83]

Answer:

x=5/3

x= 3+2\sqrt{2}

x=  3-2\sqrt{2}

Step-by-step explanation:

if graphed the x intercepts would be (5/3 , 0) (3+2\sqrt{2} ) (3-2\sqrt{2})

y intercepts (0,-5)

5 0
3 years ago
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