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3 years ago

15

. Mrs. Khan makes cookies for the school bake sale. She uses the equation c = 0.75x to determine the cost, c, for x cookies. Whi

ch best represents the constant rate at which cookies are sold at the bake sale?
A. 75 cookies per dollar
B. (0,0), (3, 2.25), (6, 4.25), (8,6.5)
c. 3/4 cookie per dollar
D. (0,0), (2, 1.5) (5, 3.75), (7,5.25)

1 answer:

IRINA_888 [86]3 years ago

3 0

Answer:

The answer is D.

Step-by-step explanation:

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Murrr4er [49]

Here is the work to help you understand the problem.
$\frac{x+9}{8}-\frac{x+3}{x+2}$

$\mathrm{Find\:the\:least\:common\:denominator\:} \ \textgreater \ 8\left(x+2\right)$

$\mathrm{Adjust\:Fractions\:based\:on\:the\:LCD} \ \textgreater \ \frac{\left(x+9\right)\left(x+2\right)}{8\left(x+2\right)}-\frac{\left(x+3\right)\cdot \:8}{8\left(x+2\right)}$

$\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}: \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}$

$\frac{\left(x+9\right)\left(x+2\right)-8\left(x+3\right)}{8\left(x+2\right)}$

$Expand \left(x+9\right)\left(x+2\right)-8\left(x+3\right)$

$\left(x+9\right)\left(x+2\right)$
$\mathrm{Distribute\:parentheses\:using}: \left(a+b\right)\left(c+d\right)=ac+ad+bc+bd$
$Where\; a=x,\:b=9,\:c=x,\:d=2$

$x\cdot \:x+x\cdot \:2+9\cdot \:x+9\cdot \:2 \ \textgreater \ \mathrm{Add\:similar\:elements:}\:2x+9x=11x$

$xx+11x+2\cdot \:9 \ \textgreater \ \mathrm{Apply\:exponent\:rule}: \:a^b\cdot \:a^c=a^{b+c}$

$xx=\:x^{1+1}=\:x^2 \ \textgreater \ x^2+11x+2\cdot \:9 \ \textgreater \ \mathrm{Multiply\:the\:numbers:}\:9\cdot \:2=18$

$x^2+11x+18 \ \textgreater \ x^2+11x+18-8\left(x+3\right)$

$-8\left(x+3\right) \ \textgreater \ \mathrm{Distribute\:parentheses\:using}: \:a\left(b+c\right)=ab+ac$
$Where\;a=-8,\:b=x,\:c=3$

$-8\cdot \:x-8\cdot \:3 \ \textgreater \ \mathrm{Multiply\:the\:numbers:}\:8\cdot \:3=24 \ \textgreater \ -8x-24$

$x^2+11x+18-8x-24 \ \textgreater \ \mathrm{Group\:like\:terms} \ \textgreater \ x^2+11x-8x+18-24$

$\mathrm{Add\:similar\:elements:}\:11x-8x=3x \ \textgreater \ x^2+3x+18-24$

$\mathrm{Add/Subtract\:the\:numbers:}\:18-24=-6 \ \textgreater \ x^2+3x-6$

$\frac{x^2+3x-6}{8\left(x+2\right)}$

Hope this helps!

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What is the image of (-1, 1) after a dilation of 2?<br> (1,3)<br> (-2, 2)<br> (2, 2)

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The answer is b. (-2,2)

Since it is a dilation of 2, multiply each number by 2.

-1*2=-2
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So after the dilation, it would be (-2,2)

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LUCKY_DIMON [66]

Answer:

a 72

b 7

Part C)

___7_|_35+63_

_____|__9+5__

35+63=7(9+5)=714=98 or 35+63=98

Step-by-step explanation:

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The unit rate is 91...

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