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konstantin123 [22]
3 years ago
15

As you hike from the highest elevation to the lowest elevation, you find three different species of related mice. None of them a

re found at the same elevation, and the vegetation changes at each elevation level.Using species C as a reference, you find that there are more genetic differences between species A and species C than between species A and species B. Which of the following statements would best reflect the mode of speciation in these mice?-Speciation was allopatric or peripatric, but would depend on the number of individuals that dispersed from the original population.-Only genetic drift is responsible for the differences observed.-Species C arose from species A later than species B.speciation was allopatric or peripatric, but would depend on the number of individuals that dispersed from the original populations.
Biology
1 answer:
Nikitich [7]3 years ago
6 0

Answer:

Speciation was allopatric or peripatric, but would depend on the number of individuals that dispersed from the original populations.

Explanation:

The new species can be formed in one of the three ways that are allopatric, peripatric, and parapatric speciation.

The allopatric speciation gives rise to new species due to the geographical barriers present between them and the peripatric speciation occurs when a small population enters into a new habitat.

In the given question, species A is more closely related to species B as to species C. This could be due to the allopatric speciation or peripatric speciation but it would depend on the number of the individuals of the population that dispersed to a different elevation which provided a new niche.

Thus, the selected option is correct.

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Question- Experimentation is broken into 2 parts, data and procedure.

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3 years ago
Is the process of passing characteristics from parent to offspring.
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true or false: All substances can pass freely between the intracellular and extracellular fluids through a phospholipid bilayer.
Komok [63]

Answer:

False

Explanation:

IF this were true this would jeopardize internal environment of our cells, similar to how not every key opens a key lock, not every molecule has the "key" to enter the intracellular and extracellular fluids through a phospholipid bilayer. Usually small hydrophobic ("water-hating") can pass through the intracellular and extracellular fluids through a phospholipid bilayer.

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All of the following statement explains why nuclear reactors considered nonrenewable resource except:
padilas [110]

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a

Explanation:

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In a chromosome, The distance between A to B is 15cM(CentiMorgan), B to C is 9cM , A to C is 6cM. If A to D is is 5cM, then what
Talja [164]

Answer:

The recombinant percentage C to D is 1% = 1cM  (Option 1)    

Explanation:

Two genes that are very close will have a few recombination events and are strongly bounded.

To calculate the recombination frequency, we have to know that 1% of recombinations = 1 map unit = 1 centiMorgan. And that the maximum recombination frequency is always 50%.  

The map unit is the distance between the pair of genes for which every 100 meiotic products, one results in a recombinant one.  

Available data:

  • In a chromosome, there are 4 genes under study, A, B, C, and D
  • Distance A-B = 15 cM
  • Distance B-C = 9 cM
  • Distance A-C = 6cM
  • Distance A-D = 5 cM

The recombinant percentage between C and D equals their distances in centiMorgan. So we need to see the order of the genes on the chromosome.

  • First, we need to identify the genes located in the extremes. These are the most distant from each other. A-B are 15 cM appart.

----A-----------------------------------------------------B---

     ║----------------------15 cM ---------------------║

  • Now that we placed both genes, we can place the other genes. The second most distant are B-C = 9cM and then A-C = 6 cM

----A------------------C--------------------------------B---

    ║------6 cM-----║----------- 9 cM-----------║

  • Finally, we can place D, which is 5 cM appart from A

----A-----------D-----C--------------------------------B---

   ║---5cM--║

Now that we can visualize better the location of genes on the chromosome, we can figure out the distance between D-C.

If the distance from A to C is 6 cM, and the distance from A to D is 5 cM, We just need to perform a subtraction, and we will get the distance from D to C.

(C-D) = (A-C) - (A-D) = 6 cM - 5 cM = 1 cM

----A-----------D-----C--------------------------------B---

                   ║1cM║

6 0
3 years ago
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