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klio [65]
4 years ago
5

PLZ HELP ASAP AREA OF A SECTOR

Mathematics
1 answer:
xxTIMURxx [149]4 years ago
5 0
The relationship of arcs is:
 S '/ S = ((1/9) * pi * 3) / (2 * pi * 3)
 Rewriting we have:
 S '/ S = ((1/9)) / (2)
 S '/ S = 1/18
 Therefore, the area of the shaded region is:
 A '= (S' / S) * A
 Where A: area of the complete circle:
 A '= (1/18) * pi * r ^ 2
 A '= (1/18) * pi * (3) ^ 2
 A '= (1/18) * pi * 9
 A '= (1/2) * pi
 Answer:
 
The area of the shaded region is:
 A '= (1/2) * pi
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Amanda [17]
The graph shows the maximum residual is ...
  ◉  Data point (10, 10); Residual = 4.50

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6 0
3 years ago
5x^2-3y^2-20x+6y+2=0 what is the value of a
butalik [34]
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4 0
3 years ago
If we list all the natural numbers below 20 that are multiples of 7 or 11, we get 7, 11 and 14. The sum of these multiples is 32
velikii [3]
Number of multiples of 7 up to 1337: \left\lfloor\dfrac{1337}7\right\rfloor=191
Number of multiples of 11 up to 1337: \left\lfloor\dfrac{1337}{11}\right\rfloor=121
Number of multiples of 77 up to 1337: \left\lfloor\dfrac{1337}{77}\right\rfloor=17

This means there are 191+121-17=295 distinct multiples of 7 *or* 11 up to 1337.

The sum of these multiples is

\displaystyle\sum_{k=1}^{191}7k+\sum_{k=1}^{121}11k-\sum_{k=1}^{17}77k

which can be computed using the well-known formula,

\displaystyle\sum_{k=1}^nk=\dfrac{n(n+1)}2

So you have

\displaystyle\sum_{k=1}^{191}7k+\sum_{k=1}^{121}11k-\sum_{k=1}^{17}77k=7\dfrac{191\times192}2+11\dfrac{121\times122}2-77\dfrac{17\times18}2=197762
8 0
3 years ago
Hello, I wanted an answer from a mathematician. The number 1.04 is closer to the number 1, 2, 1.25 or 1.5.
nevsk [136]

Answer:

the answer is 1

Step-by-step explanation:

1.25, 2 and 1.5 are too big compare to 1

3 0
3 years ago
If 4a=9b what is the value of 2b/a?
azamat

Answer:

  8/9

Step-by-step explanation:

Multiply the given equation by 2/(9a).

  4a(2/(9a)) = 9b(2/(9a))

  8/9 = 2b/a

4 0
4 years ago
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