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galina1969 [7]
2 years ago
14

- 12 = 2 + 5d + 2d ................

Mathematics
2 answers:
aleksley [76]2 years ago
5 0

\huge\text{Hey there!}

\large\textsf{-12 = 2 + 5d + 2d}

\large\text{FLIP the EQUATION}

\large\textsf{2 + 5d + 2d = -12}

\large\text{COMBINE the LIKE TERMS}

\large\textsf{\underline{(5d + 2d)} + \bf{(2)}}\large\textsf{ = (-12)}

\large\textsf{5d + 2d = \underline{7d}}

\large\textsf{2 = \bf 2}

\large\textsf{-12 = -12}

\rightarrow\large\text{New equation: }\large\textsf{7d + 2 = -12}

\large\textsf{7d + 2 = -12}

\large\text{SUBTRACT by 2 to BOTH SIDES}

\large\textsf{7d + 2 - 2 = -12 - 2}

\large\text{CANCEL out: \textsf{2 - 2} because that gives you \textsf{0}}

\large\text{Keep: \textsf{-12 - 2}}\large\text{ because it helps you solve for d}}

\large\textsf{-12 - 2 = -14}

\rightarrow\large\text{New equation: \text{\underline{7d} = -14}}

\large\textsf{7d = -14}

\large\text{DIVIDE 7 to BOTH SIDES}

\mathsf{\dfrac{7d}{7}=\dfrac{-14}{7}}

\large\text{Cancel out: }\mathsf{\dfrac{7}{7}}\large\text{ because it gives you 1}

\large\text{Keep: }\mathsf{\dfrac{-14}{7}}\large\text{ because it helps you solve  for d}

\mathsf{\dfrac{-14}{2}=-14\div 7\rightarrow \bf d}

\large\text{Solve above and you will have your d {(aka your answer)}}\uparrow

\mathsf{\dfrac{-14}{7}=\bf -2}

\boxed{\boxed{\large\text{Answer: \huge \bf d = -2}}}\huge\checkmark

\text{Good luck on your assignment and enjoy your day!}

~\frak{Amphitrite1040:)}

zmey [24]2 years ago
4 0

Answer:

-2

Step-by-step explanation:

12=2+7d

7d= -12-2

7d= -14

d= -14

-----

7

d= -2

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3 years ago
Find out the number of combinations and the number of permutations for 8 objects taken 6 at a time. Express your answer in exact
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The permutation formula is expressed as

\begin{gathered} P^n_r=\frac{n!}{(n-r)!} \\  \end{gathered}

The combination formula is expressed as

\begin{gathered} C^n_r=\frac{n!}{(n-r)!r!} \\  \\  \end{gathered}

where

\begin{gathered} n\Rightarrow total\text{ number of objects} \\ r\Rightarrow number\text{ of object selected} \end{gathered}

Given that 6 objects are taken at a time from 8, this implies that

\begin{gathered} n=8 \\ r=6 \end{gathered}

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Number of permuations:

\begin{gathered} P^8_6=\frac{8!}{(8-6)!} \\ =\frac{8!}{2!}=\frac{8\times7\times6\times5\times4\times3\times2!}{2!} \\ 2!\text{ cancel out, thus we have} \\ \begin{equation*} 8\times7\times6\times5\times4\times3 \end{equation*} \\ \Rightarrow P_6^8=20160 \end{gathered}

Number of combinations:

\begin{gathered} C^8_6=\frac{8!}{(8-6)!6!} \\ =\frac{8!}{2!\times6!}=\frac{8\times7\times6!}{6!\times2\times1} \\ 6!\text{ cancel out, thus we have} \\ \frac{8\times7}{2} \\ \Rightarrow C_6^8=28 \end{gathered}

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7 0
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we have

\pi=3.14

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A=(3.14)(5)^{2}=78.5\ m^{2}

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