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Komok [63]
4 years ago
11

The length and width of a certain rectangle are both decreased by 50%. If the length and width of the new rectangle are then inc

reased by 40%, the area of the resulting rectangle is what percent less than the area of the original rectangle?
Mathematics
1 answer:
alina1380 [7]4 years ago
5 0
51% less.

The length is decreased by 50%, which is the same as being multiplied by 0.5, then it's increased by 40% which is another multiplication by 1.4. So the overall change is 0.5 * 1.4 = 0.7, or the newest rectangle is 70% of the size of the original rectangle. And since the area increases by the square, the newest rectangle has 0.7 * 0.7 = 0.49 of the area as the original rectangle. So it has 51% less area than the original rectangle.

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Reflect triangle A in the line y=x
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Answer:

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Step-by-step explanation:

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So the image of (6,5) = (5,6)

(6, 3) ---> ( 3, 6)

(5,3) ---> (3, 5).

Note that the coordinates are reversed in each case.

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3 years ago
What is the answer of this attachment:
Solnce55 [7]

Answer:

(B) 2

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=> \frac{\sqrt{32}+ \sqrt{48} }{\sqrt{8}+\sqrt{12}  }

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=> \frac{4(\sqrt{2}+\sqrt{3})  }{2(\sqrt{2}+\sqrt{3)}  }

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