If my quadrilateral has one pair of parallel sides, and one pair of equal sides, what MUST it be, and what COULD it be? (18 Poin
1 answer:
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<h3>Answer: Choice A</h3>
- Domain: x > 4
- Range: y > 0
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Explanation:
We want to avoid having a negative number under the square root. Solving leads to
So it appears the domain could involve x = 4 itself; however, if we tried that x value, then we'd get a division by zero error.
So in reality, the domain is x > 4.
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The range of y = sqrt(x) is the set of positive real numbers. So y > 0 is the range for this equation. Shifting left and right does not affect the range, so the range of y = sqrt(x-4) is also y > 0.
We are dividing a positive number (3) over some positive number in the denominator. Overall, the expression is positive because positive/positive = positive.
Therefore, the range of the given equation is y > 0
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The graph is shown below. We have a vertical asymptote at x = 4 and a horizontal asymptote at y = 0. The green curve is fenced in the upper right corner (northeast corner).
Answer:
The coordinates of P' are (4.8,-4.8).
Step-by-step explanation:
The rule of dilation represent the dilation with scale factor 2.4 and center at origin.
If the scale factor of the dilation is k and the center is (0,0), then
Since the scale factor is 2.4, therefore
From the given figure it is noticed that the coordinates of P are (2,-2). The coordinates of P' are
Therefore the coordinates of P' are (4.8,-4.8).
<h3>The base area of triangular prism container is 42.8 cubic centimeter</h3>
<em><u>Solution:</u></em>
<em><u>The volume of triangular prism is given as:</u></em>
Given that,
A triangular prism container is full of water of 428 cubic cm
The water is 10 cm deep
Therefore,
v = 428 cubic cm
h = 10 cm
<em><u>Substituting the values we get,</u></em>
Thus the base area of triangular prism container is 42.8 cubic centimeter