Answer:
The probability that the town has 30 or fewer residents with the illness = 0.00052.
Step-by-step explanation:
So, we have the following set of data or information or parameters given from the question above and they are; the number of people living in that particular society/community/town = 74,000 residents and the proportion of people that the diseases affected = .000215.
The first step to do is to determine the expected number of people with disease. Thus, the expected number of people with disease = 74,000 × .000215 = 15.91.
Hence, the probability that the town has 30 or fewer residents with the illness = 1.23 × 10^-7 × 15.91^30/ 2.65253 × 10^-32 = 0.00052.
Note the formula used in the calculating the probability that the town has 30 or fewer residents with the illness = e^-λ × λ^x/ x!
Option C: 
is the value of a and b
Explanation:
Given that the expression 
We need to determine the value of a and b
Let us consider the term 
and take the prime factorization of the term 648
Thus, we have,
648 divides by 2,
324 divides by 2,
162 divides by 2,
81 divides by 3,
27 divides by 3,
9 divides by 3,
Thus, we have,
Therefore, equating the powers of 2 and 3, we get,
Hence, the value of a and b is 3 and 4
Thus, Option C is the correct answer.
Answer:
6x=0.10x< 2
Step-by-step explanation:
