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USPshnik [31]
3 years ago
13

Employees from A and company B receive annual bonuses. What information would you need to test the claim that the difference in

annual bonuses is greater than $100 at the 0.5 level of significance? Write out the hypothesis and explain the testing procedure in details
Mathematics
1 answer:
lyudmila [28]3 years ago
7 0

Answer:

1. The required information are

The average annual bonuses, \bar {x}_1 received by employees from company A

The average annual bonuses, \bar {x}_2 received by employees from company B

The standard deviation, σ₁, of the average annual bonuses for employees from company A

The standard deviation, σ₂, of the average annual bonuses for employees from company A

The number of employees in company A, n₁

The number of employees in company B, n₂

2. The null hypothesis is H₀: \bar {x}_1 - \bar {x}_2 ≤ 100

The alternative hypothesis is Hₐ: \bar {x}_1 - \bar {x}_2 > 100

Step-by-step explanation:

1. The required information are

The average annual bonuses, \bar {x}_1 received by employees from company A

The average annual bonuses, \bar {x}_2 received by employees from company B

The standard deviation, σ₁, of the average annual bonuses for employees from company A

The standard deviation, σ₂, of the average annual bonuses for employees from company A

The number of employees in company A, n₁

The number of employees in company B, n₂

2. The null hypothesis is H₀: \bar {x}_1 - \bar {x}_2 ≤ 100

The alternative hypothesis is Hₐ: \bar {x}_1 - \bar {x}_2 > 100

The z value for the hypothesis testing of the difference between two means is given as follows;

z=\dfrac{(\bar{x}_{1}-\bar{x}_{2})}{\sqrt{\frac{\sigma_{1}^{2} }{n_{1}}-\frac{\sigma _{2}^{2}}{n_{2}}}}

At 0.5 level of significance, the critical z_\alpha = ± 0

The rejection region is z > z_\alpha and z < -z_\alpha

Therefore, the value of z obtained from the relation above more than or less than 0, we reject the null hypothesis, and we fail to reject the alternative hypothesis.

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Triss [41]

Answer:

Step-by-step explanation:

I will give each that is a statistical question

Subject the students in my class like.

Number of students in my class (as you could compare to another class)

height of each student

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Perhaps height (As you could compare it to the average height)

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3 0
2 years ago
Read 2 more answers
What fraction of 3 is 2 2/5
Yuki888 [10]

Answer: 2 2/5 is 4/5 of 3

Step-by-step explanation:

We can view that as what do we multiply 3 by to get 2 2/5 and call that value x

3x = 2 2/5

x = (2 2/5)/3

Let's turn 2 2/5 into an improper fraction... 2 2/5 = 12/5

So we have

x = (12/5)/3 = (12/5)(1/3) = 4/5

Thus 2 2/5 is 4/5 of 3

Verify:  3(4/5) = 12/5 = 2 2/5

5 0
2 years ago
PLEASE HELP!
Wittaler [7]

Answer:

See below

Step-by-step explanation:

Use the formulae directly

For a cone, with base radius = r and height = h, here are the related formula

\textrm{Slant height  l} = \sqrt{r^2 + h^2}  (1)

\textrm{Lateral surface area} = \pi r l

\textrm {Base area} = \pi r^2

\textrm { Total Surface Area SA} = \textrm{Base Area + Lateral Area} = \pi r^2 + \pi rl = \pi r(r + l) (2)

\textrm{Volume V = } (1/3)  \pi r^2h (3)

Therefore directly plugging in the numbers in the above equations:

Note:

l = slant height in cm
SA = total surface area in sqcm
V = Volume in cubic cm

Figure(a)

r = 4, h = 8

\textrm{l} = \sqrt{4^2 + 8^2} =\sqrt{80} = 8.944 \\\textrm{SA}  = 4\pi(4 + 8.944) =  4\pi(12.944) = 162.66\\\textrm{V} = (1/3)\pi(4^2)(8) = 134.04

Figure(b)

r = 7, h =15

\textrm{l} = \sqrt{7^2 + 15^2} =\sqrt{274} = 16.55

\textrm{SA}  = 7\pi(7 + 16.55) =  517.89

Figure (c)

r = 5, l = 8

h = \sqrt{l^2 - r^2} = \sqrt{8^2 - 5^2} = \sqrt{39} = 6.245\\SA = \textrm{SA}  = 5\pi(5 + 8) =  204.2\\V = (1/3)\pi(5^2)(6.245) = 163.5


6 0
2 years ago
2x^2 / x^2 - y^2 - x^2 / xy - y ^ 2​
Juliette [100K]

Answer:

2 - 2y^2 - x/y

Step-by-step explanation:

2x^2/x^2 = 2

and

x^2/xy = x/y

therefore

2x^2/x^2 - y^2 - x^2/xy - y^2

= 2 - y^2 - x/y - y^2

= 2 - y^2 - y^2 - x/y

= 2 - 2y^2 - x/y

6 0
3 years ago
Drag and drop the correct angle measures onto the diagram
svlad2 [7]

Answer:

Here you go!

Hope this helps!

7 0
2 years ago
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