Answer:
270
Step-by-step explanation:
We're minimizing

subject to

. Using Lagrange multipliers, we have the Lagrangian

with partial derivatives

Set each partial derivative equal to 0:

Subtracting the second equation from the first, we find

Similarly, we can determine that

and

by taking any two of the first three equations. So if

determines a critical point, then

So the smallest value for the sum of squares is

when

.
<h3>2
Answers: Choice B and Choice D</h3>
==========================================================
Explanation:
Standard form will always have the largest exponents listed first on the left side. Then as you move to the right, the exponents will decrease. Choice B shows this with the exponents counting down (3,2). Choice D is a similar story with the exponents counting down (9,2,1,0). Think of -6x as -6x^1, and also think of the 10 as 10x^0.
Something like choice A is a non-answer because the term with the largest exponent 3 is buried in the middle, and not at the left side. The exponents are not in decreasing order. Choice C can be ruled out for similar reasons.
Side note: the largest exponent is the degree of the polynomial. This only applies to single variable polynomials.
Answer:69
Step-by-step explanation:
Answer:
r u finding the slope? bc the slope is -3/1.5
the y intercept is -3
the x intercept is -1.5
Step-by-step explanation:
hope this helped!!! and if i didnt, im sorryyy!!