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3 years ago

-8 3/4 dived by 2 1/6

Mathematics

2 answers:

Zepler [3.9K]3 years ago

8 0

Answer:

Improper Fraction: -105/26

Mixed Number: -4/1/26

Decimal: −4.038

Hope this helps

-Amelia

bekas [8.4K]3 years ago

6 0

Answer:-4.03846153846

Step-by-step explanation:

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By using algebra properties and trigonometric formulas we find that the trigonometric expression $\frac{1}{1 - \sin x} - \frac{1}{1 + \sin x}$ is equivalent to the trigonometric expression $\frac{2\cdot \tan x}{\cos x}$ .

<h3>How to prove a trigonometric equivalence by algebraic and trigonometric procedures</h3>

In this question we have trigonometric expression whose equivalence to another expression has to be proved by using algebra properties and trigonometric formulas, including the fundamental trigonometric formula, that is, cos² x + sin² x = 1. Now we present in detail all steps to prove the equivalence:

$\frac{1}{1 - \sin x} - \frac{1}{1 + \sin x}$ Given.

$\frac{1 + \sin x - 1 + \sin x}{1 - \sin^{2}x}$ Subtraction between fractions with different denominator / (- 1) · a = - a.

$\frac{2\cdot \sin x}{\cos^{2}x}$ Definitions of addition and subtraction / Fundamental trigonometric formula (cos² x + sin² x = 1)

$\frac{2\cdot \tan x}{\cos x}$ Definition of tangent / Result

By using algebra properties and trigonometric formulas we conclude that the trigonometric expression $\frac{1}{1 - \sin x} - \frac{1}{1 + \sin x}$ is equal to the trigonometric expression $\frac{2\cdot \tan x}{\cos x}$ . Hence, the former expression is equivalent to the latter one.

To learn more on trigonometric equations: brainly.com/question/10083069

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