The first one = 5 and the second one = -6
hope this helps
Answer:
The correct answer is first option
u² - 11u + 24 = 0
When u = (x² - 1)
Step-by-step explanation:
It is given that,
(x² - 1)² - (x² - 1) + 24 = 0
<u>To find the correct answer</u>
Substitute u = x² - 1
The equation becomes,
u² - 11u + 24 = 0 Where u = (x² - 1)
Therefore the correct answer is first option
u² - 11u + 24 = 0
When u = (x² - 1)
Answer: the mode is 67.2
Step-by-step explanation:
Given that;
Data Frequency
30 - 34 1
35 - 39 0
40 - 44 3
45 - 49 7
50 - 54 5
55 - 59 10
60 - 64 10
65 - 69 21
70 - 74 12
Mode = ?
we know that mode is the number that has the highest number of appearance of frequency, so in this case, the data group that has the highest frequency (21) is 65 - 69
Lower class boundary of the modal group; L = 65
Frequency of the group before the modal group; Fm-1 = 10
Frequency of the modal group; Fm = 21
Frequency of the group after the modal group; Fm+1 = 12
Group width; G = 4
Now using the formula
Mode = L + [ (Fm - Fm-1) / ( (Fm - Fm-1) + (Fm - Fm+1) ) ] × W
so we substitute
Mode = 65 + [ (21 - 10) / ( (21 - 10) + (21 - 12) ) ] × 4
= 65 + [ 11 / 20] × 4
= 65 + 2.2
= 67.2
Therefore the mode is 67.2
11 ⅓ gallons.
Explanation:
Since she sold 3⅓ gallons more on Sunday than she did on Saturday, you need to add 10⅔+3⅓. ⅓+⅔=3/3, or 1. 10+3=13, and 13+1=14. She sold 14 gallons on Sunday.
On Monday, she sold 2⅔ less than she did on Sunday, so we need to do 14-2⅔. 14-2 is 12, and 12-⅔= 11⅓. This means that she sold 11⅓ gallons on Monday.
Hope this helps :)
Answer:
68%
Step-by-step explanation:
