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3 years ago

What are two factors of -45 that add up to 3 and multiply to -45?

Mathematics

1 answer:

zheka24 [161]3 years ago

3 0

45=9*5=3*15
clearly, none of these factors have a sum of 3 considering a negative factor

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Julius is buying beverages for brunch. He needs to buy a total of 5

xeze [42]

Well, he only needs 5 gallons of beverages. Because he buys two containers of each, however, that means he bought 320 gallons total (I would say). How I got my answer:

There are 8 pints in a gallon (8 x 2)
There are 4 quarts in a gallon (4 x 2)
There are 16 cups in a gallon (16 x 2)
There are 128 ounces in a gallon (128 x 2)

With that being said, we can add these to find the total amount of gallons of beverages Julius bought. 16 + 8 + 8 + 32 + 256 = 320.

Hopefully this helps!

7 0

2 years ago

Which graph shows the best solution for the system of linear equations. x+5y_>5 y_<2x+4

Mkey [24]

Answer:

Step-by-step explanation:

8 0

3 years ago

For the second quarter of 2015, Apple sold 61.0 million iPhones. This represented a year- over-year increase of 40%. What were t

Anastaziya [24]

Answer:

It sold 43.57 iPhones for the same quarter in the previous year.

Step-by-step explanation:

It sold 61.0 million iPhone, which is an increase of 40% over the value of the previous year x.

This can be interpreted as:

61 million is 140% = 1.4 of the previous year amount, that is, x. So

$1.4x = 61$

$x = \frac{61}{1.4}$

$x = 43.57$

It sold 43.57 iPhones for the same quarter in the previous year.

4 0

3 years ago

Use Stokes' Theorem to evaluate C F · dr where C is oriented counterclockwise as viewed from above. F(x, y, z) = xyi + 5zj + 7yk

REY [17]

By Stokes' theorem,

$\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S$

where $S$ is the surface with $C$ as its boundary. The curl is

$\nabla\times\vec F(x,y,z)=2\,\vec\imath-x\,\vec k$

Parameterize $S$ by

$\vec\sigma(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec\jmath+(8-u\cos v)\,\vec k$

with $0\le u\le9$ and $0\le v\le2\pi$ . Then take the normal vector to $S$ to be

$\vec\sigma_u\times\vec\sigma_v=u\,\vec\imath+u\,\vec k$

Then the line integral is equal to the surface integral,

$\displaystyle\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S=\int_0^{2\pi}\int_0^9(2\,\vec\imath-u\cos v\,\vec k)\cdot(u\,\vec\imath+u\,\vec k)\,\mathrm du\,\mathrm dv$