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aleksklad [387]
3 years ago
9

Rachel is a nurse. She earns 12 vacation days after working 768 hours. How many hours does racheal need to work to earn 1 vacati

on day?
Mathematics
1 answer:
Minchanka [31]3 years ago
3 0

Answer:

64 Hours

Step-by-step explanation:

768/12 = 64

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The corrdinates of point h are 3,-2 wich point has the coordinates -3,2​
timofeeve [1]

Answer: h

Step-by-step explanation: since point h corrdinates of 3,-2 and u wanna find 3,-2 the answers is in the question

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3 years ago
I need help with this fast
Citrus2011 [14]

Answer:

Step-by-step explanation:

g( - 4) = \sqrt[3]{- 4 + 4} = 0

( - 4, 0)

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3 years ago
Two catalysts may be used in a batch chemical process. Twelve batches were prepared using catalyst 1, resulting in an average yi
aalyn [17]

Answer:

a) t=\frac{(91-85)-(0)}{2.490\sqrt{\frac{1}{12}}+\frac{1}{15}}=6.222  

df=12+15-2=25  

p_v =P(t_{25}>6.222) =8.26x10^{-7}

So with the p value obtained and using the significance level given \alpha=0.01 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis.

b) (91-85) -2.79 *2.490 \sqrt{\frac{1}{12} +\frac{1}{15}} =3.309

(91-85) +2.79 *2.490 \sqrt{\frac{1}{12} +\frac{1}{15}} =8.691

Step-by-step explanation:

Notation and hypothesis

When we have two independent samples from two normal distributions with equal variances we are assuming that  

\sigma^2_1 =\sigma^2_2 =\sigma^2  

And the statistic is given by this formula:  

t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}}+\frac{1}{n_2}}  

Where t follows a t distribution with n_1+n_2 -2 degrees of freedom and the pooled variance S^2_p is given by this formula:  

\S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}  

This last one is an unbiased estimator of the common variance \sigma^2  

Part a

The system of hypothesis on this case are:  

Null hypothesis: \mu_2 \leq \mu_1  

Alternative hypothesis: \mu_2 > \mu_1  

Or equivalently:  

Null hypothesis: \mu_2 - \mu_1 \leq 0  

Alternative hypothesis: \mu_2 -\mu_1 > 0  

Our notation on this case :  

n_1 =12 represent the sample size for group 1  

n_2 =15 represent the sample size for group 2  

\bar X_1 =85 represent the sample mean for the group 1  

\bar X_2 =91 represent the sample mean for the group 2  

s_1=3 represent the sample standard deviation for group 1  

s_2=2 represent the sample standard deviation for group 2  

First we can begin finding the pooled variance:  

\S^2_p =\frac{(12-1)(3)^2 +(15 -1)(2)^2}{12 +15 -2}=6.2  

And the deviation would be just the square root of the variance:  

S_p=2.490  

Calculate the statistic

And now we can calculate the statistic:  

t=\frac{(91-85)-(0)}{2.490\sqrt{\frac{1}{12}}+\frac{1}{15}}=6.222  

Now we can calculate the degrees of freedom given by:  

df=12+15-2=25  

Calculate the p value

And now we can calculate the p value using the altenative hypothesis:  

p_v =P(t_{25}>6.222) =8.26x10^{-7}

Conclusion

So with the p value obtained and using the significance level given \alpha=0.01 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis.

Part b

For this case the confidence interval is given by:

(\bar X_1 -\bar X_2) \pm t_{\alpha/2} S_p \sqrt{\frac{1}{n_1} +\frac{1}{n_2}}

For the 99% of confidence we have \alpha=1-0.99 = 0.01 and \alpha/2 =0.005 and the critical value with 25 degrees of freedom on the t distribution is t_{\alpha/2}= 2.79

And replacing we got:

(91-85) -2.79 *2.490 \sqrt{\frac{1}{12} +\frac{1}{15}} =3.309

(91-85) +2.79 *2.490 \sqrt{\frac{1}{12} +\frac{1}{15}} =8.691

7 0
3 years ago
Evaluate each logarithm. Do not use a calculator. Log (125)(1/25)
svetlana [45]

Answer:

-2/3

Step-by-step explanation:

Log125(1/25)=x

Raise each side to the base of 125

125^Log125(1/25)=125^x

1/25 = 125^x

Rewrite 25 as a power of 5  and 125 as a power of 5

1 / 5^2 = 5^3^x

The if power is in the denominator, we can bring it to the numerator by making it negative

5^-2 = 5^3^x

We know that a^b^c = a^(b*c)

5^-2 = 5^(3*x)

Since the bases are the same, the exponents are the same

-2 = 3x

Divide by 3

-2/3 = 3x/3

-2/3 =x

6 0
3 years ago
What type of equations could have extraneous solutions?
SVETLANKA909090 [29]

Answer:

id

Step-by-step explanation:

4 0
3 years ago
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