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Marta_Voda [28]
2 years ago
7

What value of x is in the solution set of 8x – 6 > 12 + 2x?

Mathematics
1 answer:
sveta [45]2 years ago
8 0
The solution to your equation is

x=3
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A fruit stand has to decide what to charge for their produce. They need $10 for 44 apples and 44 oranges. They also need $15 for
Bess [88]

Step-by-step explanation:

Let x be the price of an apple and y be the price of an orange.

We have been given that a fruit stand need $10 for 4 apples and 4 oranges. We can represent this information as:

4x+4y=10...(1)

We are also told that they need $15 for 6 apples and 6 oranges. We can represent this information as:

6x+6y=15...(2)

Therefore, our desired system of equations will be:

4x+4y=10...(1)

6x+6y=15...(2)


4 0
3 years ago
Franklin bought 10.7 pounds of potatoes and 0.74 pounds of carrots. How many pounds of vegetables did he buy in all?
Greeley [361]

Answer:

brainiest give promise

Step-by-step explanation:

27.9 pounds

24.37 + 3.53 = 27.9

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2 years ago
if someone apply to 5 different colleges and 4 different majors how many different scenarios are there
svetoff [14.1K]

Answer:

He can apply for 4 different majors at each college giving

5 * 4 = 20     (if the college permits more than 1 application for a major)

4 0
2 years ago
Can you form a triangle with these given side lengths? 12 , 8 , 16<br><br> Please help me!!!!
Scilla [17]

Answer:

yes

Step-by-step explanation:

12+8>16

the two short sides have to be greater than the longest dude when combined and that is true so you can form a triangle

6 0
3 years ago
Read 2 more answers
Suppose that 35 people are divided in a random manner into two teams in such a way that one team contains 10 people and the othe
Effectus [21]

Answer:

0.5798 or 57.98%

Step-by-step explanation:

The total number of ways to form the two teams is the combination of choosing 10 people out of 35 (₃₅C₁₀). The number of possibilities that A and B are both on the 10-people team is given by the combination of choosing 8 people (since two are fixed) out of 33 (₃₃C₈).The number of possibilities that A and B are both on the 25-people team is given by the combination of choosing 10 people out of 33 (₃₃C₈).

Therefore, the probability that two particular people A and B will be on the same team is:

P = \frac{_{33}C_8+_{33}C_{10}}{_{35}C_{10}} \\\\P=\frac{\frac{33!}{(33-8)!8!}+\frac{33!}{(33-10)!10!} }{\frac{35!}{(35-10)!10!}} \\\\P=\frac{69}{119} = 0.5798

The probability is 0.5798 or 57.98%.

8 0
2 years ago
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