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oee [108]
3 years ago
15

How do you solve 2/3-1/4

Mathematics
2 answers:
agasfer [191]3 years ago
6 0
Before you can add or subtract fractions, they must have a common denominator.

-- Find a common denominator for [ something/3 ] and [ something/4 ].

-- When you have both of the fractions changed to a common denominator, you can just subtract the second numerator from the first one, and write that difference over the same common denominator.
slavikrds [6]3 years ago
6 0
You have to find the least common denominator, which in this case would be 12.

8/12- 3/12= 5/12
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Describe a real world situation that can be modeled by the equation y=1/20x
MariettaO [177]

Your neighbor will let you take water from the well on his claim,
charging you $.05 a quart.

If 'x' is the number of quarts you take from his well on Tuesday, then
'y' is the amount of money you owe him before the sun goes down.

3 0
3 years ago
8B+18C=4 <br> Solve for B
hammer [34]

Answer:

b=1/2-9/4c

Step-by-step explanation:

first get B on one side

8b+18c=4

    -18c    -18c

8b=4-18c

divide both sides by 8

8b=4-18c

/8   /8 /8

b=1/2-9/4c

8 0
3 years ago
One number is 16 more than another number. The two numbers have a sum of 120. Wbich system of equations could you use to find th
joja [24]

Step-by-step explanation:

Let, 1st number be x and 2nd number be y

Then,

equation 1

x = 16+y

equation 2

x + y = 120

or, y = 120 - x

now,

x = 16 + y

or, x= 16 + 120 - x (putting the value of y from equation 2 )

or, x + x = 136

or, 2x =136

or, x= 136/2

or, x =68

Then,

y = 120-x

or, y= 120- 68 (putting the value of x)

or, y= 52

Hence, the two numbers are 68 and 52.

5 0
3 years ago
Can two events with nonzero probabilities be both independent and mutually​ exclusive? Choose the correct answer below. A. ​Yes,
Flura [38]

Answer:

Step-by-step explanation:

B. ​No, two events with nonzero probabilities cannot be independent and mutually exclusive because if two events are mutually​ exclusive, then when one of them​ occurs, the probability of the other must be zero.

For two mutually exclusive events , with non- zero probabilities , when one occurs , the other can not happen . In this way they become dependent events . In this way , for two events to be both independent and mutually exclusive , at least one of the two events must have zero probability .

3 0
3 years ago
A small basket holds 75% as much as a large basket.
Serggg [28]

Answer:

-33

Step-by-step explanation:

hope you get it right

5 0
3 years ago
Read 2 more answers
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