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oee [108]
3 years ago
15

How do you solve 2/3-1/4

Mathematics
2 answers:
agasfer [191]3 years ago
6 0
Before you can add or subtract fractions, they must have a common denominator.

-- Find a common denominator for [ something/3 ] and [ something/4 ].

-- When you have both of the fractions changed to a common denominator, you can just subtract the second numerator from the first one, and write that difference over the same common denominator.
slavikrds [6]3 years ago
6 0
You have to find the least common denominator, which in this case would be 12.

8/12- 3/12= 5/12
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(Picture) MULTIPLYING POLYNOMIALS AND SIMPLIFYING EXPRESSIONS PLEASE HELP!!!!
Sidana [21]

Answer:

-2p^2-11p-35

Step-by-step explanation:

-2(p+4)^2-3+5p

First we square the parenthesis. Apply FOIL method to multiply

(p+4)^2= (p+4)(p+4)= p^2 + 4p+4p+16= p^2+8p+16

-2(p^2+8p+16) -3+5p

distribute -2 inside the parenthesis

-2p^2-16p-32-3+5p

Now combine like terms

-2p^2-11p-35


3 0
3 years ago
Someone help me please and thank you!! ASAP :(
pantera1 [17]
<h3>Answer: Choice D) </h3>

Work Shown:

(f+g)(x) = f(x)+g(x)\\\\(f+g)(x) = \frac{x-23}{x^2+9x-36}+\frac{1}{x+12}\\\\(f+g)(x) = \frac{x-23}{(x+12)(x-3)}+\frac{1(x-3)}{(x+12)(x-3)}\\\\(f+g)(x) = \frac{x-23+1(x-3)}{(x+12)(x-3)}\\\\(f+g)(x) = \frac{x-23+x-3}{x^2+9x-36}\\\\(f+g)(x) = \frac{2x-26}{x^2+9x-36}\\\\

We must require that x \ne -12 and x \ne 3 to avoid having 0 in the denominator. This is why choice D is the answer.

3 0
3 years ago
Which of the following are valid names for the triangle below? Check all that apply
AlexFokin [52]

Answer:

equilateral, isosceles, and scalene

Step-by-step explanation:

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3 years ago
The period of the function y=sin(1/4 x) is equal to
Aleonysh [2.5K]

Answer:

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2 years ago
What is 4/5 - 3/7 in simplest form
rusak2 [61]
4/5 -3/7=
28/35 -15/35
=13/35

4 0
3 years ago
Read 2 more answers
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