Find the y intercept and slope

Mathematics

1 answer:

Naya [18.7K]3 years ago

6 0

Okay so first off the equation of a line is
Y=mx+b
m= the slope
b= the y intercept

The Y intercept of this line is 2 and the slope is 5/3! You know this is the slope because if you start at point a and go up 5 and to the right 3, you end up at point b.

The equation for this line would be y=5/3x+2

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5. Solve the equation z^2 + 4z - 9 = 0 by completing the square.

Luba_88 [7]

Answer:

A. Z = 2 + N13

Step-by-step explanation:

Let's solve your equation step-by-step.

0=z2+4z−9

Step 1: Subtract z^2+4z-9 from both sides.

0−(z2+4z−9)=z2+4z−9−(z2+4z−9)

−z2−4z+9=0

For this equation: a=-1, b=-4, c=9

−1z2+−4z+9=0

Step 2: Use quadratic formula with a=-1, b=-4, c=9.

−b±√b2−4ac

−(−4)±√(−4)2−4(−1)(9)

2(−1)

4±√52

−2

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8 0

3 years ago

A company introduces a new product for which the number of units sold S is

KonstantinChe [14]

(a) The "average value" of a function over an interval [a,b] is defined to be

(1/(b-a)) times the integral of f from the limits x= a to x = b.

Now S = 200(5 - 9/(2+t))

The average value of S during the first year (from t = 0 months to t = 12 months) is then:

(1/12) times the integral of 200(5 - 9/(2+t)) from t = 0 to t = 12

or 200/12 times the integral of (5 - 9/(2+t)) from t= 0 to t = 12

This equals 200/12 * (5t -9ln(2+t))

Evaluating this with the limits t= 0 to t = 12 gives:

708.113 units., which is the average value of S(t) during the first year.

(b). We need to find S'(t), and then equate this with the average value.

Now S'(t) = 1800/(t+2)^2

So you're left with solving 1800/(t+2)^2 = 708.113

I'll leave that to you

6 0

3 years ago

Mafalda has a save percentage of 0.7380.7380, point, 738 so far this hockey season. Last season, her save percentage was 0.5850.

Snowcat [4.5K]

Answer:

0.153

Step-by-step explanation:

We have been given that Mafalda has a save percentage of 0.738 so far this hockey season. Last season, her save percentage was 0.585.

To find improvement in Mafalda's save percentage we will subtract last season's save percentage from this season's save percentage.

$0.738-0.585=0.153$