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cestrela7 [59]
3 years ago
13

The value of x in the equation log(x-1)9=2 is

Mathematics
2 answers:
mel-nik [20]3 years ago
4 0
\log_{(x-1)} 9=2

the domain:
x-1 >0 \ \land \ x-1 \not=1 \\
x>1 \ \land \ x \not= 2 \\
x \in (1; 2) \cup (2;+\infty)

the equation:
\log_{(x-1)}9=2 \\
(x-1)^2=9 \\
\sqrt{(x-1)^2}=\sqrt{9} \\
|x-1|=3 \\
x-1=3 \ \lor \ x-1=-3 \\
x=4 \ \lor \ x=-2

4 is in the domain
-2 is not in the domain

The answer:
x=4

***
Also, the answer in 13 is {8}. -3 is not in the domain. Replace x with -3 and you'll see:
x=\sqrt{5x+24} \\
-3=\sqrt{5 \times (-3)+24} \\
-3=\sqrt{-15+24} \\
-3=\sqrt{9} \\
-3=3
It's not true so -3 isn't a solution to this equation.
maxonik [38]3 years ago
3 0
D:x-1>0 \wedge x\n-1\not=1\\
D:x>1 \wedge x\not=2\\
D:x\in(1,2)\cup(2,\infty)\\\\
\log_{x-1}9=2\\
(x-1)^2=9\\
x-1=3 \vee x-1=-3\\
x=4 \vee x=-2\\-2\not \in D\\
\boxed{ x=4}
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