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kozerog [31]
3 years ago
8

What is the equation of a line in general form that passes through the point (1,-2) and has a slope of 1/3

Mathematics
1 answer:
ser-zykov [4K]3 years ago
4 0

Answer:

(y+2) = (1/3)(x-1)  

Answer in point-slope form, you can rearrange this into the form which you need.

Step-by-step explanation:

recall that the general point-slope form of a linear equation looks like :

(y - y₁) = m(x - x₁)

where m is the slope and (x₁,y₁) is any point on the line

here we are given m = 1/3 and (x₁,y₁)=(1,-2)

simply substitute this info into the general equation above

(y - y₁) = m(x - x₁)

(y - (-2) ) = (1/3)(x - 1)

(y+2) = (1/3)(x-1)  Answer in point-slope form, you can rearrange this into the form which you need.

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Which is the equation in slope-intercept form for the line that passes through (3, 7)
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Answer:

y =  -  \frac{5}{3} x + 12

Step-by-step explanation:

First, rewrite the given equation in the form of y=mx+c.

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Thus, the gradient of the given equation is ⅗.

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