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3 years ago

What is the equation of a line in general form that passes through the point (1,-2) and has a slope of 1/3

Mathematics

1 answer:

ser-zykov [4K]2 years ago

4 0

Answer:

(y+2) = (1/3)(x-1)

Answer in point-slope form, you can rearrange this into the form which you need.

Step-by-step explanation:

recall that the general point-slope form of a linear equation looks like :

(y - y₁) = m(x - x₁)

where m is the slope and (x₁,y₁) is any point on the line

here we are given m = 1/3 and (x₁,y₁)=(1,-2)

simply substitute this info into the general equation above

(y - y₁) = m(x - x₁)

(y - (-2) ) = (1/3)(x - 1)

(y+2) = (1/3)(x-1) Answer in point-slope form, you can rearrange this into the form which you need.

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Which expression is equivalent to?

guapka [62]

Answer: $\frac{2x\sqrt[4]{y^{2}}}{3}$

Step-by-step explanation:

$\sqrt[4]{\frac{16}[81}} \sqrt[4]{\frac{x^{11}y^{8}}{x^{7}y^{6}}}\\\\=\frac{2}{3} \sqrt[4]{x^{4}y^{2}}\\\\=\frac{2x\sqrt[4]{y^{2}}}{3}$

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2 years ago

If you draw four cards at random from a standard deck of 52 cards, what is the probability that all 4 cards have distinct charac

mezya [45]

There are $\binom{52}4$ ways of drawing a 4-card hand, where

$\dbinom nk = \dfrac{n!}{k!(n-k)!}$

is the so-called binomial coefficient.

There are 13 different card values, of which we want the hand to represent 4 values, so there are $\binom{13}4$ ways of meeting this requirement.

For each card value, there are 4 choices of suit, of which we only pick 1, so there are $\binom41$ ways of picking a card of any given value. We draw 4 cards from the deck, so there are $\binom41^4$ possible hands in which each card has a different value.

Then there are $\binom{13}4 \binom41^4$ total hands in which all 4 cards have distinct values, and the probability of drawing such a hand is

$\dfrac{\dbinom{13}4 \dbinom41^4}{\dbinom{52}4} = \boxed{\dfrac{2816}{4165}} \approx 0.6761$

4 0

2 years ago

WILL MARK BRANLIEST!! 15 POINTS!!

mihalych1998 [28]

Corresponding angles

3 0

3 years ago

Calculate (A⃗ ×B⃗ )⋅C⃗ for the three vectors A⃗ with magnitude A = 5.08 and angle θA = 25.6 ∘ measured in the sense from the +x

alexgriva [62]

Answer:

(A⃗ ×B⃗ )⋅C⃗ = - 76.415

Step-by-step explanation:

First we need to calculate (A⃗ ×B⃗ ) :

(A⃗ ×B⃗ ) = A.B.sin (α).n

Where A is the magnitude of A⃗

Where B is the magnitude of B⃗

Where α is the angle between A⃗ and B⃗ = 63.9 - 25.6 = 38.3

Finally n is the vector orthogonal to A⃗ and B⃗

n magnitude is 1 and his direction is given by the right hand-rule

so n = ( 0 , 0 , 1 )

(A⃗ ×B⃗ ) = A.B.sin (α).n = 5.08 . 3.94 . sin (38.3) . (0 , 0 , 1 ) = (0,0,12.4)

C⃗ can be written as C.(0,0,-1) because of his +z - direction

C.(0,0,-1) = 6.16.(0,0,-1) = (0,0,-6.16)

(A⃗ ×B⃗ )⋅C⃗ = (0,0,12.4).(0,0,-6.16) = -76.41480787 = -76.415

8 0

3 years ago

Which pair of angles are corresponding angles?

Effectus [21]

Corresponding angles are angles that are the same, and occupy the same relative position.

1 and 2: Incorrect - These are supplementary angles

3 and 5: Incorrect - These are same-side interior angles

2 and 6: Correct - These are corresponding angles

4 and 7: Incorrect - These are alternate interior angles

Hope this helps!! :)

7 0

2 years ago