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WINSTONCH [101]

3 years ago

14

Type no, one, or infinite to complete the statement. Type only lowercase letters. Do not type spaces in your answer. 3x - 4y = 6

6x - 8y = 10

1 answer:

julsineya [31]3 years ago

3 0

Answer:infinite both can e simplifies

Step-by-step explanation:

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Combine like terms <br> 9j+34j

MA_775_DIABLO [31]

The answer is 43j you just have to add them together

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The angles of a rectangle are equal.<br> always<br> sometimes<br> never

worty [1.4K]

Answer: A rectangles angles are always equal.

Step-by-step explanation:

Suppose you have a rectangle, four sides, two pairs of parallel lines. in order to be a rectangle, the quadrilateral has to have equal angles, similar to a square, if they didn't, they could be a trapezoid, which is not a rectangle, because it only has one pair of parallel lines.

Hope this helps!

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Firlakuza [10]

Answer:

Option D.

Step-by-step explanation:

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2 years ago

Choose the best system of equations to represent the situation and determine the labels for the variables:

7nadin3 [17]

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2 years ago

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15. If x=a Sin2t (I+Cos2t) and y=b Cos 2t (1-Cos2t) then find<br>dy/dx at =22/7*4<br>

Sav [38]

By the chain rule,

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm dy}{\mathrm dt}\dfrac{\mathrm dt}{\mathrm dx}\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\frac{\mathrm dy}{\mathrm dt}}{\frac{\mathrm dx}{\mathrm dt}}$

It looks like we're given

$\begin{cases}x=a\sin(2t)(1+\cos(2t))\\y=b\cos(2t)(1-\cos(2t))\end{cases}$

where <em>a</em> and <em>b</em> are presumably constant.

Recall that

$\cos^2t=\dfrac{1+\cos(2t)}2$

$\sin^2t=\dfrac{1-\cos(2t)}2$

so that

$\begin{cases}x=2a\sin(2t)\cos^2t\\y=2b\cos(2t)\sin^2t\end{cases}$

Then we have

$\dfrac{\mathrm dx}{\mathrm dt}=4a\cos(2t)\cos^2t-4a\sin(2t)\cos t\sin t$

$\dfrac{\mathrm dy}{\mathrm dt}=-4b\sin(2t)\sin^2t+4b\cos(2t)\sin t\cos t$

$\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{4b\cos(2t)\sin t\cos t-4b\sin(2t)\sin^2}{4a\cos(2t)\cos^2t-4a\sin(2t)\cos t\sin t}$

$\implies\boxed{\dfrac{\mathrm dy}{\mathrm dx}=\dfrac ba\tan t}$

where the last reduction follows from dividing through everything by $\cos(2t)\cos^2t$ and simplifying.

I'm not sure at which point you're supposed to evaluate the derivative (22/7*4, as in 88/7? or something else?), so I'll leave that to you.

8 0

3 years ago