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diamong [38]
3 years ago
11

Can you help me and describe how it’s done please 2ab+3ac+6ac+4ab+ab=

Mathematics
1 answer:
ziro4ka [17]3 years ago
8 0

2ab + 3ac + 6ac + 4ab + ab \\ 7ab + 9ac
You combine like terms, if the variables are the same the just add the numbers in front of them.
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A stage designer is making a rectangular drape that is 7 yards in length and 16 yards in width. The fabric for the drape cost $2
USPshnik [31]
Yard to square yard
example: 1yard*1 = 1square yard so 6*6=36 square yards.   7*7=42
36*2.90=104.40
42*2.90=121.8
104.40+121.8=$226.20
6 0
3 years ago
75 points
tekilochka [14]

-- Big D

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6 0
4 years ago
I NEED HELP PLEASE WITH THIS MATH PROBLEM THANK YOU SO MUCH FOR HELP
myrzilka [38]
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3 0
3 years ago
Please help! I know the answer but I don’t know how to work it out... Answer is 634cm^3
dsp73

Answer:634 cm and i think you add the something and a 3

Step-by-step explanation:

Photo math

3 0
3 years ago
You have 8,640 grams of a radioactive kind of cesium. If its half-life is 30 years, how much
Vikki [24]

The mass of cesium left afer 120 years if the original mass of cesium is 8640 with an half-life of 30 years,  is 540 grams.

<h3>What is half-life?</h3>

This can be defined as the time taken for half the amount of a radioactive substance to decay.

To calculate the amount of cesium left after 120 years, we use the formua below.

Formula:

  • R' = R/(2^{T/t})............. Equation 1

Where:

  • R = Original amount of Cesium
  • R' = New amount of cesium
  • T = Total time
  • t = Half-life

From the question,

Given:

  • R = 8640
  • T = 120 years
  • t = 30 years

Substitute these values into equation 1

  • R' = 8640/(2^{120/30})
  • R' = 8640/2^{4}
  • R' = 8640/16
  • R' = 540 grams.

Hence, The mass of cesium left afer 120 years is 540 grams.

Learn more about half-life here: brainly.com/question/25750315

4 0
2 years ago
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