Question

Multiply (x2 - 3x + 4) (-2x2 + 4x - 1) Express your answer in standard form I need help

Answer 1

Step-by-step explanation:

Step 1:  Distribute

$(x^2-3x+4)(-2x^2+4x-1)$

$(x^2*-2x^2)+(x^2*4x)+(x^2*-1)+(-3x*-2x^2)+(-3x*4x)+(-3x*-1)+(4*-2x^2)+(4*4x)+(4*-1)$

$(-2x^4) + (4x^3)+(-x^2)+(6x^3)+(-12x^2)+(3x)+(-8x^2)+(16x)+(-4)$

$-2x^4+4x^3+6x^3-x^2-12x^2-8x^2+16x+3x-4$

$-2x^4+10x^3-21x^2+19x-4$

Answer:  $-2x^4+10x^3-21x^2+19x-4$

Answer 2

Answer:

-2x⁴ + 10x³ - 21x² + 19x - 4

Step-by-step explanation:

(x² - 3x + 4) (-2x² + 4x - 1)

-2x⁴ + 6x³ - 8x² + 4x³ - 12x² + 16x - x² + 3x - 4

-2x⁴ + 10x³ - 21x² + 19x - 4