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fiasKO [112]
3 years ago
14

30% of all the students in a school are in a play all students except for 140 are in the play how many students are in the schoo

l
Mathematics
1 answer:
Bezzdna [24]3 years ago
3 0
To figure out how many kids are in the school, you must set up an equation with x representing the number of students. 30% of the students are in the play, so that would be represented by 0.3x. We also know that 140 students are not in the play, that could be represented by x-140. These two equations will equal each other since they both represent the same information, which is the number of children in the play. You set those two equations equal to one another (0.3x = x-140). You then can add 140 to the left side of the equation and subtract 0.3x from the right side. We do this in order to get both values of x on the same side of the equation. We then can simplify the right side of the equation by subtracting 0.3x from 1x. We get 0.7x. Our equation now looks like 140 = 0.7x. We must now divide each side of the equation by 0.7 in order to get the x all by itself and find its value. 140 divided by 0.7 is 200. The number of students in the school is 200.
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3 0
2 years ago
Can someone help me round these two numbers? I completely forgot how ‍
tigry1 [53]

Answer:

Step-by-step explanation:

If you are rounding to nearest tenth

2.6  1.9

Nearest hundredth

2.6   1.87

If the number to the right of the one you want to round is 5 or above, you go up a number. If it's below, you go down 1.

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5 0
2 years ago
Can somebody help me do this, please
natta225 [31]

Step-by-step explanation:

For the triangle on the bottom right the missing angle is

180- (74+50)= 56°

For the triangle on the bottom left the missing angle is

180- (45+80)= 55°

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3 0
2 years ago
In circle E, AC=4, CG=6, and AH=3, Find HB and EG. If necessary, round to the tenths place.
bezimeni [28]
Using theorem about secant segments we can write,
AB*AH=AG*AC
AC=4,
CG=6
AG=AC+CG=4+6=10
AH=3
AB= AH+HB=AH+x=3+x
(3+x)*3=10*4
9+3x=40
3x=40-9
3x=31
x=31/3≈10.3
HB≈10.3
EG=HB/2 (as radius and diameter)
EG=10.3/2≈5.2




3 0
3 years ago
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