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jek_recluse [69]
3 years ago
8

If you were to rotate ABCD 180degrees about the origin, what would the coordinate of A' be?

Mathematics
2 answers:
Drupady [299]3 years ago
8 0

Answer:

5,5

Step-by-step explanation:

Olin [163]3 years ago
7 0
It would be (-3 ,-5) because the rule for rotating 180 degrees is (x,y)>(-x.-y)
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Please help me ..<br>Use the distributive property to factor the expression.<br>2k + 10<br>​
Aleksandr [31]

Answer:

2×(1+10)

Step-by-Step

You are just substituting in where the parenthesis go.

But I am not entirely sure.

5 0
3 years ago
Can someone explain what to do here I’m very confused?
Grace [21]
Start by distributing the - 1/3 which is the same as dividing the entire parentheses by 3 which results in (3x+10)
4 0
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Write in slope intercept form an equation of the line<br> (1, 2); m = -2
mr Goodwill [35]
Y = 2
X = 1
M = -2
B = ?
y=mx+b
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6 0
3 years ago
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Likurg_2 [28]
1 white shirt
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7 0
3 years ago
Does the series converge or diverge? If it converges, what is the sum? Show your work. ∑ ∞ n = 1 − 4 ( − 1 / 2 ) n − 1
Mekhanik [1.2K]

Answer:

Step-by-step explanation:

Given the series,

∑ ∞ n = 1 − 4 ( − 1 / 2 ) n − 1

I think the series is summation from n = 1 to ∞ of -4(-1/2)^(n-1)

So,

∑ − 4 ( − ½ )^(n − 1). From n = 1 to ∞

There are different types of test to show if a series converges or diverges

So, using Ratio test

Lim n → ∞ (a_n+1 / a_n)

Lim n → ∞ (-4(-1/ 2)^(n+1-1) / -4(-1/2)^(n-1))

Lim n → ∞ ((-4(-1/2)^(n) / -4(-1/2)^(n-1))

Lim n → ∞ (-1/2)ⁿ / (-1/2)^(n-1)

Lim n→ ∞ (-1/2)^(n-n+1)

Lim n→ ∞ (-1/2)^1 = -1/2

Since the limit is less than 0, then, the series converge...

Sum to infinity

Using geometric progression formula

S∞ = a / 1 - r

Where

a is first term

r is common ratio

So, first term is

a_1 = -4(-½)^1-1 = -4(-½)^0 = -4 × 1

a_1 = -4

Common ratio r = a_2 / a_1

a_2 = 4(-½)^2-1 = -4(-½)^1 = -4 × -½ = 2

a_2 = 2

Then,

r = a_2 / a_1 = 2 / -4 = -½

S∞ = -4 / 1--½

S∞ = -4 / 1 + ½

S∞ = -4 / 3/2 = -4 × 2 / 3

S∞ = -8 / 3 = -2⅔

The sum to infinity is -2.67 or -2⅔

Check attachment for better understanding

3 0
3 years ago
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