Answer:
B and D
Step-by-step explanation:
Given:
Christopher scores 2 goals in a soccer game.
His goal total can vary from the average by 1 goal.
To find:
The absolute value equation can be used to calculate Christopher's maximum and minimum goals per game.
Solution:
Let Christopher scores x goals in a soccer game.
Then difference between actual goals and average goals is x-2.
His goal total can vary from the average by 1 goal.
Maximum number of goals = 2+1 = 3
Minimum number of goals = 2-1 = 1
It means, the difference between actual goals and average goals is either -1 and 1.
...(1)
...(2)
Using (1) and (2),we get
Therefore, the correct option is C.
Answer:
no. see below
Step-by-step explanation:
This much of Josh's working is correct:
x^2-6x=7
x^2-6x+9=7+9
(x-3)^2=16
At this point Josh apparently overlooked the fact that he needed to take the square root of both sides of the equation. Had he done that, he would have ...
x -3 = ±4
x = 3+4 . . . or . . . 3 -4
x = 7 or -1
_____
Josh reported values of x that would match ...
x -3 = ±16
He <em>violated the equal sign</em> by taking the square root on the left, and multiplying by ±1 on the right. Doing different operations on the two sides of the equation will mean the value of x is changed to something other than what you're looking for.
Answer:
3
Step-by-step explanation:
4(x + 1) + 8 = 24
Subtract 8 from each side
4(x + 1) + 8-8 = 24-8
4(x + 1) = 16
Divide by 4
4(x+1)/4 = 16/4
x+1 = 4
Subtract 1
x+1-1 = 4-1
x=3
Imagine a right triangle where a and b are the legs and c is the hypothenuse.
Pitagora: a²+b²=c²
Divide by c
(a/c)²+(b/c)²=1
But a/c=sin(B) and b/c=cos(B)
Thus sin² + cos² = 1
