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2 years ago

How people will 4 pies feed if you gave each person one sixth of the pie?

Mathematics

1 answer:

Kruka [31]2 years ago

5 0

There are 4 pies each person gets 1/6
so 4 times 6 is 24
so it would feed 24 people

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The Cool Company determines that the supply function for its basic air conditioning unit is S(p) = 10 + 0.002p3 and that its dem

Radda [10]

Answer: At $21.85, the supply will equal to demand.

Step-by-step explanation:

Since we have given that

Demand function is given by

$D(p) = 50 - 0.04p^2, \text{where p is the price.}$

Supply function is given by

$S(p) = 10 + 0.002p^3$

According to question, we need to find the price for which the supply equals the demand, i.e. Equilibrium price and quantity.

$D(p)=S(p)\\\\50-0.04p^2=10+0.002p^3\\\\50-10=0.002p^3+0.04p^2\\\\40=\frac{2}{1000}p^3+\frac{4}{100}p^2\\\\40=\frac{2}{100}p^2(\frac{1}{10}p+2)\\\\\frac{40\times 100}{2}=p^2(\frac{1p+20}{2})\\\\\mathrm{The\:Newton-Raphson\:method\:uses\:an\:iterative\:process\:to\:approach\:one\:root\:of\:a\:function}\\\\p\approx \:21.85861\dots$

So, at $21.85, the supply will equal to demand.

3 0

2 years ago

Read 2 more answers

Evaluate the line integral by the two following methods. xy dx + x2 dy C is counterclockwise around the rectangle with vertices

Airida [17]

Answer:

25/2

Step-by-step explanation:

Recall that for a parametrized differentiable curve C = (x(t), y(t)) with the parameter t varying on some interval [a, b]

$\large \displaystyle\int_{C}[P(x,y)dx+Q(x,y)dy]=\displaystyle\int_{a}^{b}[P(x(t),y(t))x'(t)+Q(x(t),y(t))y'(t)]dt$

Where P, Q are scalar functions

We want to compute

$\large \displaystyle\int_{C}P(x,y)dx+Q(x,y)dy=\displaystyle\int_{C}xydx+x^2dy$

Where C is the rectangle with vertices (0, 0), (5, 0), (5, 1), (0, 1) going counterclockwise.

a) Directly

Let us break down C into 4 paths $\large C_1,C_2,C_3,C_4$ which represents the sides of the rectangle.

$\large C_1$ is the line segment from (0,0) to (5,0)

$\large C_2$ is the line segment from (5,0) to (5,1)

$\large C_3$ is the line segment from (5,1) to (0,1)

$\large C_4$ is the line segment from (0,1) to (0,0)

Then

$\large \displaystyle\int_{C}=\displaystyle\int_{C_1}+\displaystyle\int_{C_2}+\displaystyle\int_{C_3}+\displaystyle\int_{C_4}$

Given 2 points P, Q we can always parametrize the line segment from P to Q with

r(t) = tQ + (1-t)P for 0≤ t≤ 1

Let us compute the first integral. We parametrize $\large C_1$ as

r(t) = t(5,0)+(1-t)(0,0) = (5t, 0) for 0≤ t≤ 1 and

r'(t) = (5,0) so

$\large \displaystyle\int_{C_1}xydx+x^2dy=0$

Now the second integral. We parametrize $\large C_2$ as

r(t) = t(5,1)+(1-t)(5,0) = (5 , t) for 0≤ t≤ 1 and

r'(t) = (0,1) so

$\large \displaystyle\int_{C_2}xydx+x^2dy=\displaystyle\int_{0}^{1}25dt=25$

The third integral. We parametrize $\large C_3$ as

r(t) = t(0,1)+(1-t)(5,1) = (5-5t, 1) for 0≤ t≤ 1 and

r'(t) = (-5,0) so

$\large \displaystyle\int_{C_3}xydx+x^2dy=\displaystyle\int_{0}^{1}(5-5t)(-5)dt=-25\displaystyle\int_{0}^{1}dt+25\displaystyle\int_{0}^{1}tdt=\\\\=-25+25/2=-25/2$

The fourth integral. We parametrize $\large C_4$ as

r(t) = t(0,0)+(1-t)(0,1) = (0, 1-t) for 0≤ t≤ 1 and

r'(t) = (0,-1) so

$\large \displaystyle\int_{C_4}xydx+x^2dy=0$

$\large \displaystyle\int_{C}xydx+x^2dy=25-25/2=25/2$

Now, let us compute the value using Green's theorem.

According with this theorem

$\large \displaystyle\int_{C}Pdx+Qdy=\displaystyle\iint_{A}(\displaystyle\frac{\partial Q}{\partial x}-\displaystyle\frac{\partial P}{\partial y})dydx$

where A is the interior of the rectangle.

so A={(x,y) | 0≤ x≤ 5, 0≤ y≤ 1}

We have

$\large \displaystyle\frac{\partial Q}{\partial x}=2x\\\\\displaystyle\frac{\partial P}{\partial y}=x$

$\large \displaystyle\iint_{A}(\displaystyle\frac{\partial Q}{\partial x}-\displaystyle\frac{\partial P}{\partial y})dydx=\displaystyle\int_{0}^{5}\displaystyle\int_{0}^{1}xdydx=\displaystyle\int_{0}^{5}xdx\displaystyle\int_{0}^{1}dy=25/2$

3 0

2 years ago

Hey! pls help me with this question on angles. would really be appreciated. have a nice day.

Neko [114]

Using supplementary angles, it is found that the measures of the angles are given as follows:

m<a = 30º.

m<b = 90º.

<h3>What are supplementary angles?</h3>

Supplementary angles are two angles whose sum is of 180º.

An interior angle is supplementary with it's exterior angle, hence:

m<a + 150º = 180º -> m<a = 30º.

The sum of the three interior angles of a triangle is of 180º, hence:

30º + m<b + 60º = 180º

90º + m<b = 180º

m<b = 90º.

More can be learned about supplementary angles at brainly.com/question/12919120

#SPJ1

7 0

1 year ago

Think of the letter X as four vectors starting from the center and pointing outward. Label the four vectors starting from the to

laila [671]

Answer:

a) in

b) in

Step-by-step explanation:

The detailed explanation is attached below

5 0

2 years ago

PLEASEEEE HELP THIS IS DUE TODAY!!!

avanturin [10]

Answer: $200

Step-by-step explanation:

On the X axis, it shows the kilograms. Since the problem asks for how much money she makes for 60 kg, go to the point on the X axis that represents 60 kg and then go up to the corresponding y or dollar value, which is 200.

8 0

2 years ago