Let the length of the isosceles sides be s respectively,
the hypotenuse will be sqrt(2).s
so 2s+sqrt(s).s = 2P
-> s = 2P/(2+sqrt(2))
since its a isosceles right angled triangle, it's area is half of a square with the same side
area = s^2/2 = 2P^2/(2+sqrt(2))^2
Falling at the rate of 2.5 m/s for 45 seconds, the anchor fell
(2.5 m/s) x (45 s) = 112.5 meters .
If it wound up only 40 meters underwater, then it must have fallen
(112.5 m - 40 m) = 72.5 meters
from its storage position on the big cruise ship,
before it ever reached the water.
Since it was falling at the rate of 2.5 m/s, it took
(72.5 m) / (2.5 m/s) = 29 seconds
to get down to the water surface after it started dropping.
Answer:
is it an abc or what??
Step-by-step explanation: