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just olya [345]
3 years ago
13

The final velocity, V, of an object under constant acceleration can be found using the formula V2= v2 + 2as, where v is the init

ial velocity (in meters per second), a is acceleration (in meters per second), and s is the distance (in meters). What is the formula solved for a?
Mathematics
1 answer:
neonofarm [45]3 years ago
6 0

Whenever you work any "solve for" problem, you start by looking at what is done to the variable of interest. Here, a is multiplied by 2s and added to v². You must reverse these operations, generally in reverse order.

V² -v² = 2as . . . . . . . . subtract v²

(V² -v²)/(2s) = a . . . . . divide by the coefficient of a

Solved for a, the formula is ...

... a = (V² -v²)/(2s)

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bija089 [108]

Answer:

  • x = 2

Step-by-step explanation:

<u>x is side of right triangle with other sides:</u>

  • √20 and 8/2 = 4

<u>Then x is:</u>

  • x² = √20² - 4²
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8 0
2 years ago
Find the slope of each line
sladkih [1.3K]

Step-by-step explanation:

To find the Slope of each line, pick two points you can clearly identify on each graph. The first graph has a point (-5,5) and (4,-5). Using these two points find the difference of the y coordinates divided by the difference in the x coordinates, like this:

5 - (-5). = 10

-5 - 4 = - 9

So the Slope is - 10/9

Same steps for all. Your equation is

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3 0
3 years ago
49767269 x 327686000 - 1029 + 1101 / 32
mars1129 [50]

Answer:

16308037309533006\frac{13}{32}

Step-by-step explanation:

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= 16308037309534000 - 1029 + \frac{1101}{32}

= 16308037309532972 + 34\frac{13}{32}

= 16308037309533006\frac{13}{32}

8 0
3 years ago
Jocelyn estimates that a piece of wood measures 5.5 cm. If it actually measures 5.62 cm, what is the percent error of Jocelyn's
morpeh [17]
The percent error is -2.1352% of Jocelyn's estimate. May I have Brainless
8 0
3 years ago
Read 2 more answers
What is the center and radius of the circle?<br> (x-3)2 + y² = 4
Kipish [7]

Answer:

center = (3, 0)

radius = 2

Step-by-step explanation:

Standard equation of a circle:  \sf (x-h)^2+(y-k)^2=r^2

(where (h, k) is the center of the circle and r is the radius)

Given equation:

\sf (x-3)^2+y^2=4

Rewrite in standard form:

\sf \implies (x-3)^2+(y-0)^2=2^2

Therefore

  • center = (3, 0)
  • radius = 2
4 0
2 years ago
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