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3 years ago

100 POINTS! WILL BE MARKED BRAINLIEST!!

Mathematics

1 answer:

QveST [7]3 years ago

5 0

KE = 0 (because velocity is 0)

PE = mgh = 2kg*9.8m/s^2*40m= 784 joule

<u>Explanation:</u>

KE stands for kinetic energy. In physics, the kinetic energy of an object is the energy that it possesses due to its motion. It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity.

Having gained this energy during its acceleration, the body maintains this kinetic energy unless its speed changes. Since in this case, the building is still and therefore it does not have any kind of kinetic energy because there is not acceleration.

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What is the pattern between 1/4, 1/2, 3/4, and 1

bagirrra123 [75]

Answer:

Adding 1/4 each time

Step-by-step explanation:

1/4+1/4=1/2

1/2+1/4=3/4

3/4+1/4=1

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3 years ago

1. 51=-7x-6(-4x+17)<br><br>2. 184=-2x+6(5x-16)<br><br>Solve for x

Afina-wow [57]

Answer:

1- x= 9

2- x= 10...............

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2 years ago

What is 2/3 divided by 4 in the Simplest form?

dsp73

Answer:

2/3 divided by 4 = .16

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3 years ago

Read 2 more answers

Someone pls answer this it’s so confusing lol

GenaCL600 [577]

Answer:

Step-by-step explanation:

w = yh - 2yc³

First of all factorize y out of the expression on the right side of the equation

That's

w = y( h - 2c³)

Next divide both sides by (h - 2c³) to make y stand alone

We have

We have the final answer as

Hope this helps you

4 0

3 years ago

Simplify

Diano4ka-milaya [45]

Answer:

$\huge\boxed{\sqrt[4]{16a^{-12}}=2a^{-3}=\dfrac{2}{a^3}}$

Step-by-step explanation:

$16=2^4\\\\a^{-12}=a^{(-3)(4)}=\left(a^{-3}\right)^4\qquad\text{used}\ (a^n)^m=a^{nm}\\\\\sqrt[4]{16a^{-12}}=\bigg(16a^{-12}\bigg)^\frac{1}{4}\qquad\text{used}\ a^\frac{1}{n}=\sqrt[n]{a}\\\\=\bigg(2^4(a^{-3})^4\bigg)^\frac{1}{4}\qquad\text{use}\ (ab)^n=a^nb^n\\\\=\bigg(2^4\bigg)^\frac{1}{4}\bigg[(a^{-3})^4\bigg]^\frac{1}{4}\qquad\text{use}\ (a^n)^m=a^{nm}\\\\=2^{(4)(\frac{1}{4})}(a^{-3})^{(4)(\frac{1}{4})}=2^1(a^{-3})^1=2a^{-3}\qquad\text{use}\ a^{-n}=\dfrac{1}{a^n}$

$=2\left(\dfrac{1}{a^3}\right)=\dfrac{2}{a^3}$

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3 years ago