Answer:
C. ∆ABD ≅ ∆CBD by the SSS Postulate
Step-by-step explanation:
We can prove that ∆ABD and ∆CBD congruent by the SSS Postulate.
The SSS postulate states that of three sides in one triangle are congruent to three corresponding sides in another, therefore, the two triangles are congruent.
From the diagram shown,
AB ≅ CB,
AD ≅ CD
BD = BD
We have three sides in ∆ABD that are congruent to three corresponding sides in ∆CBD.
Therefore, ∆ABD ≅ ∆CBD by the SSS Postulate
The 3rd equation, as if you solve for x as shown, you will end up with equation x=8.




Answer:

Step-by-step explanation:
The formula for a circle of radius r centered at (h, k) is ...
(x -h)^2 +(y -k)^2 = r^2
Both of the given points are on the line y=-1. The distance between them is the difference of their x-coordinates, 2 -(-2) = 4. So, the radius of the circle is 4 and the equation becomes ...
(x -2)^2 +(y -(-1))^2 = 4^2
(x -2)^2 +(y +1)^2 = 16 . . . . . . . . . matches choice A
Answer:
1 and 2 are the answers i think
Step-by-step explanation:
Answer:
83+11_
Step-by-step explanation: