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3 years ago

ASAP! GIVING BRAINLIEST! Please read the question THEN answer correctly! No guessing. Show your work or give an explaination.

Mathematics

2 answers:

rewona [7]3 years ago

6 0

Answer:

C. 3x power 3 + 6x power 2

dedylja [7]3 years ago

4 0

The awnser is the letter C . 3x^3 + 6x^2

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3x+2y=4 8x-3y=-6 solving systems of equations by substitution

Over [174]

Answer:

x=0, y=2. (0, 2).

Step-by-step explanation:

3x+2y=4

8x-3y=-6

---------------

3(3x+2y)=3(4)

2(8x-3y)=2(-6)

-----------------------

9x+6y=12

16x-6y=-12

----------------

25x=0

x=0/25

x=0

3(0)+2y=4

0+2y=4

2y=4-0

2y=4

y=4/2

y=2

6 0

3 years ago

BRAINLY FOR CORRECT ANSWER! YOU MUST GIVE ME AN ANSWER NOT AN EQUATION.

Nadusha1986 [10]

The answer is 310.93, rounded to the nearest hundredth. Hope this helps!

5 0

3 years ago

STUDY TIP 1

Mandarinka [93]

Answer:

THANK U!

FOR THE TIP.

HAVE A GREAT DAY!

6 0

3 years ago

In a certain Algebra 2 class of 27 students, 18 of them play basketball and 16

Bogdan [553]

Answer:

The probability is 0.89 or 89%

Step-by-step explanation:

Probability

There are n=27 students in a certain Algebra 2 class. 18 out of them play basketball and 16 of them play baseball.

We also know 3 students play neither sport. This leaves 27-3=24 students playing sports.

The probability that a randomly chosen student plays basketball or baseball is:

$\displastyle p=\frac{24}{27}$

Simplifying:

$\displastyle p=\frac{8}{9}=0.89$

The probability is 0.89 or 89%

6 0

3 years ago

pls help will give brainliest Rena used the steps below to evaluate the expression (StartFraction (x Superscript negative 3 Base

kaheart [24]

Answer:

First "order of operations" mistake: step 2

First arithmetic mistake: step 4

Step-by-step explanation:

As we understand Rena's work, she wants to simplify ...

$\left(\dfrac{x^{-3}y^{-2}}{2x^4y^{-4}}\right)^{-3}$

for x = -1 and y = 2.

Her work seems to be ...

Step 1

$\text{Substitute $x=-1$ and $y=2$ into the expression}\\\\\left(\dfrac{(-1)^{-3}2^{-2}}{2(-1)^42^{-4}}\right)^{-3}\qquad\text{no error}$

Step 2

$\text{Simplify the parentheses}\\\\\left(\dfrac{2^4}{2(-1)^4(-1)^32^2}\right)^{-3}=\left(\dfrac{2^2}{2(-1)^7}\right)^{-3}\qquad\text{order of operations error}$

Step 3

$\text{Evaluate the power to a power}\\\\\dfrac{2^{-6}}{2^{-3}(-1)^{21}}\qquad\text{no error}$

Step 4

$\text{Use reciprocals and find the value}\\\\\dfrac{1}{2^32^6(-1)^{21}}=\dfrac{1}{8\cdot 64\cdot (-1)}=\dfrac{-1}{512}\qquad\text{error: $2^3$ is used instead of $2^{-3}$}$

_____

So, the first arithmetic error is in Step 4. However, the order of operations requires exponents be evaluated first. Doing that makes step 2 look like ...

$\left(\dfrac{-\dfrac{1}{4}}{2(1)\dfrac{1}{16}}\right)^{-3}=(-2)^{-3}\qquad\text{proper Step 2}$

We expect your answer is supposed to be Step 4.

7 0

3 years ago