A pharmacist has 40% and 80% of iodine solutions on hand. How many liters of each iodine solution will be required to produce 4 liters of a 50% iodine mixture?
.
Let x = liters of 40% iodine
then
4-x = liters of 80% iodine
Using algebra:
.40x + .80(4-x) = .50(4)
.40x + 3.20-.80x = 2
3.20-.40x = 2
x = 4 liters (40% iodine)
80% iodine:
4-x = 4-4 = 0 liters needed (80% iodine)
Answer:
1) 24 2) $2 per pencil 3) 23 4) 15 5) $5 per eraser
6) 37 7) 16 8) $16
Step-by-step explanation:
hope this helps
Answer:
6.0
Step-by-step explanation:
Answer:
Step-by-step explanation:
a) Maternal gene = 0.25; Paternal gene = 0.25
Probability having a birth defect = 0.25 X 0.25 = 0.625
b) P(A) = 0.30; P(B) = 0.70
P(A)*P(B) = 0.30 X 0.70 = 0.021
For marriage:
25%: P(A)*P(A)*0.25 = 0.09 X 0.25 = 0.0225
65%: P(B)*P(B)*0.65 = 0.049 X 0.65 = 0.03185
10%: P(A)*0.10 = 0.03 and P(B)*0.10 = 0.07
P(A)*P(B) = 0.03 X 0.07 = 0.0021
Probability of a defect birth in the next generation = 0.0225 + 0.03185 + 0.0021 = 0.05645
c) 1. P(A)*P(A) = 0.09
2. P(B)*P(B) = 0.049
3. P(A)*P(B) = 0.021
