We have to find the GCD between 10, 16 and 4 and between x^5, x^4 and x^2
GCD (10,16,4) = 2
GCD (x^5,x^4,x^2) = x^2
So we divide all terms for 2x^2
Final result: 2x^2(5x^3-8x^2+2)
Hello from MrBillDoesMath!
Answer:
7/3 and 14/3 inches
Discussion:
Let P1 = "Piece 1" and "P2 = Piece 2", Then P2 = 2 * P1 and
P1 + P2 = 7 => as P2 = 2 P1
P1 + 2P1 = 7 =>
3P1 = 7 => divide both sides by 7
P1 = 7/3
Then P2 = 2 P1 - 2* (7/3) = 14/3
Thank you,
MrB
Answer:
A) 7x^3 + 13x^2 + 8x + 9
Step-by-step explanation:
(3x^2 + 2x + 7x^3) + (10x^2 + 6x + 9)
I like to line them up vertically
7x^3 +3x^2 + 2x
+ (10x^2 + 6x + 9)
-----------------------------------
7x^3 +13x^2 +8x +9
To solve any algebraic equation, we want to get x by itself. Here, x is accompanied by 3.6. So that means we have to get rid of 3.6. To get rid of 3.6, one can either subtract 3.6 from both sides or add -3.6 to each side.
