We have been given graph of a downward opening parabola with vertex at point
. We are asked to write equation of the parabola in standard form.
We know that equation of parabola in standard form is
.
We will write our equation in vertex form and then convert it into standard form.
Vertex for of parabola is
, where point (h,k) represents vertex of parabola and a represents leading coefficient.
Since our parabola is downward opening so leading coefficient will be negative.
Upon substituting coordinates of vertex and point (0,0) in vertex form, we will get:




Divide both sides by 
So our equation in vertex form would be
.
Let us convert it in standard from.



Therefore, the equation of function is standard form would be
.
6(3x+5)
6*3x=18x
6*5=30
<u>18x+30</u> is your answer! I hope this helped! :)
Answer:
-4
Step-by-step explanation:
-10 - (-6)
Remove the brackets:
-10 - - 6
Remember that all negative and negative values are always positive because they are the same; if they are different, for instance, a positive value and a negative value, then that value will be a negative value.
Continue solving:
-10 - - 6
- and - are positive values
- 10 + 6
= - 4
Therefore the answer is 4
MN goes through
Slope:-
Slope of perpendicular line:-
Passes through k(3,-3)
Equation in point slope form
- y-y1=m(x-x1)
- y+3=-5(x-3)
- y+3=-5x+15
- y=-5x+12
Check one by one
- 0=-5(-12)+12=60+12=72
- 2=-5(2)+12=-10+12=2
Yes option B is correct