2x2 + x −#6 _____________
x2 − 1
∙ x
__
2 + 2x + 1
x 2 − 4
Rewrite as multiplication.
(2x − 3)(x + 2) __
(x + 1)(x − 1) ∙ (x + 1)(x + 1) __ (x + 2)(x − 2) Factor the numerator and denominator.
(2x − 3)(x + 2)(x + 1)(x + 1) ___ (x + 1)(x − 1)(x + 2)(x − 2) Multiply numerators and denominators.
(2x − 3)(x + 2)(x + 1)(x + 1) ___ (x + 1)(x − 1)(x + 2)(x − 2) Cancel common factors to simplify.
(2x − 3)(x + 1) __ (x − 1)(x − 2)
Answer:
4/5
Step-by-step explanation:
- -18/2 = -9, and integer
- √9 = 3, an integer
- 0, an integer
- 4/5, irreducible fraction; not an integer
Answer:
JKCA DASVAN OVAJKDJVNAJjkkfkav
Step-by-step explanation:
Answer:
3 + 3p
Step-by-step explanation:
since there's no equal sign or no value that it shows all of that added together is equivalent to it's not really equal to anything. However if you're asking what that equation would look like if you simplified it down , then it would be 3 + 3p because you combine the like terms
Answer:
2
Step-by-step explanation:
So I'm going to use vieta's formula.
Let u and v the zeros of the given quadratic in ax^2+bx+c form.
By vieta's formula:
1) u+v=-b/a
2) uv=c/a
We are also given not by the formula but by this problem:
3) u+v=uv
If we plug 1) and 2) into 3) we get:
-b/a=c/a
Multiply both sides by a:
-b=c
Here we have:
a=3
b=-(3k-2)
c=-(k-6)
So we are solving
-b=c for k:
3k-2=-(k-6)
Distribute:
3k-2=-k+6
Add k on both sides:
4k-2=6
Add 2 on both side:
4k=8
Divide both sides by 4:
k=2
Let's check:
:
I'm going to solve 
for x using the quadratic formula:
Let's see if uv=u+v holds.
Keep in mind you are multiplying conjugates:
Let's see what u+v is now:
We have confirmed uv=u+v for k=2.
