I assume (x-4)3 means (x-4)³. What we wish is to set the derivative equal to zero.
Expanding the T(x) polynomial makes it easier for me to take the derivative.
So (x-4)³ = x³ - 12x² + 48x - 64 + 6
T'(x) = 3x² - 24x + 48
We can factor out a 3 and set this to zero:
x² - 8x + 16 = 0
(x -4)² = 0
x = 4 should therefore represent the turning point.
I am mildly chagrined, I almost used the f'(x) = nx^(n-1) function at first, which appears would have been correct.
Its A sorry i didnt show you my work did it on a peice of paper
Without values for the other variables, I assume you're asking for a literal equation.
12y+d=-19y+t
31y+d=t
31y=-d+t
y=(-d+t)/31
Answer:4
Step-by-step explanation:
Answer:the length of the rectangle is 28
The width of the rectangle is 16
Step-by-step explanation:
The given equations are set up to determine the dimensions of a rectangle. L represents the length of the rectangle. W represents the width of the rectangle. Let us label
2L + 2W = 88 as equation 1.
We would substitute L = W + 12 into equation 1, it becomes
2(W + 12) + 2W = 88
2W + 24 + 2W = 88
4W + 24 = 88
4W = 88 - 24 = 64
W = 64/4 = 16
Substituting W = 16 into L = W + 12, it becomes
L = 16 + 12 = 28
