(2·3.5 + 4·3.25 + 2·1.9 + 1·1.2)·(1 - 0.05) = $23.75
If we let x and y represent the prices of adult and child tickets, respectively, then we can write two equations based on the daily sales.
8x +5y = 108
x +14y = 67
A graphing calculator shows the solution of these equations to be
(x, y) = (11, 4)
The price of an adult ticket is $11.
The price of a child ticket is $4.
If the change in the number of pounds is p, the change in the cost will be $11c.
This is because each pound costs $11.
Nothing. Say that you substitute 3 for 'z.' 6(3) is the same as (3)6. Simple.